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arsen [322]
3 years ago
11

Which box of crackers is a better deal?

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

Since each cracker in the 190 gram box costs $ 0.0078 while the 850 gram box costs $ 0.0082 each, the 190 gram box is a better deal.

Step-by-step explanation:

Knowing that a 190-gram box of crackers costs $ 1.49 and an 850-gram box costs $ 6.99, to determine which of them is a better deal, the following calculation must be performed:

1.49 / 190 = 0.0078

6.99 / 850 = 0.0082

Therefore, since each cracker in the 190 gram box costs $ 0.0078 while the 850 gram box costs $ 0.0082 each, the 190 gram box is a better deal.

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What is the x- coordinate of the zero of the graphed line?
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Answer:

4

Step-by-step explanation:

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When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression?
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Distribute -

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The body temperatures of adults are normally distributed with a mean of 98.6degrees° F and a standard deviation of 0.60degrees°
Schach [20]

Answer:

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 98.6, \sigma = 0.6, n = 36, s = \frac{0.6}{\sqrt{36}} = 0.1

If 36 adults are randomly​ selected, find the probability that their mean body temperature is greater than 98.4degrees° F.

This is 1 subtracted by the pvalue of Z when X = 98.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{98.4 - 98.6}{0.1}

Z = -2

Z = -2 has a pvalue of 0.0228

1 - 0.0228 = 0.9772

97.72% probability that their mean body temperature is greater than 98.4degrees° F.

6 0
3 years ago
Forty-two tickets at $10.50 each cost? _______
Vikki [24]

Answer:

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Step-by-step explanation:

Since each ticket costs 10.50 and you buy 42 :

10.5 * 42 = 441

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