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Rom4ik [11]
3 years ago
11

A bowl is in the shape of a hemisphere (half a sphere) with a diameter of 13 inches. Find the volume of the bowl. Use 3.14 for p

i, and round to the nearest cubic inch.
Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

575in³

Step-by-step explanation:

Volume for a Sphere = 4/3πr³

Radius = 13/2 = 6.5

4/3(3.14)(6.5³) = 1149.763333

Because it's half a sphere, just divide by 2

1149.763333/2 = 574.881667

Rounded to the nearest cubic inch = 575

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14(5-1/5×25)+2÷4×1 How Do I Evaluate This Expression ?
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Use the distributive property and multiply everything in the parentheses by 14.
Leaving you with.. (70 - 3.5 x 350) + 2 / 4 x 1.
Then reduce the parentheses. 
Leaving you with.. ( -1155) + 2 / 4 x 1
Then divide 2 by four.
Leaving you with.. (-1155) + .5
Answer..   -1,154.5
7 0
3 years ago
Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p
GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2

you replace t1 from the first equation in the second equation:

(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}

Then, for t2 = 0 and t2=1/2 you obtain for t1:

t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths  intersect are:

r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)

B) You have the following two trajectories of two independent particles:

r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t

From the first equation you have:

t=1+2t\\\\t=-1

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0
3 years ago
Most college-bound students take either the SAT(Scholastic Assessment Test) or the ACT (which originally stood for American coll
Jlenok [28]

Answer:

Luis would need to have a SAT score of 574.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Nicole's z-score:

ACT scores have a mean of about 21 with a standard deviation of about 5, which means that \mu = 21, \sigma = 5

Nicole gets a score of 24, which means that X = 24. Her z-score is:

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 21}{5}

Z = 0.6

What score would Luis have to have on the SAT to have the same standardized score(z-score) as Nicole's standardized score on the ACT?

Luis would have to get a score with a z-score of 0.6, that is, X when Z = 0.6.

SAT scores have a mean of about 508 with a standard deviation of about 110, which means that \mu = 508, \sigma = 110.

The score is:

Z = \frac{X - \mu}{\sigma}

0.6 = \frac{X - 508}{110}

X - 508 = 0.6*110

X = 574

Luis would need to have a SAT score of 574.

8 0
2 years ago
a store sells new DVDs for $12 each. used DVDs sell for $7 each. Joseph is buying two new DVDs and X used DVDs. write an equatio
vagabundo [1.1K]
Given that new DVDs are selling for $12 and used for $7, then Joseph is buying:
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7 0
3 years ago
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A survey was taken of students in math classes to find out how many hours per day students spend
Hoochie [10]

Answer:

1. Mean, because there are no outliers that affect the center

Step-by-step explanation:

Second period: 3,2,3,1,3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

Sorted values : 0, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4

The mean = ΣX / n

n = sample size, n = 15

Mean = 34 / 15 = 2.666

The median = 1/2(n+1)th term.

1/2(16)th term = 8th term.

The 8th term = 2

The best measure of centre is the mean because the values for the second period has no outliers that might have affected the centre of the distribution.

Both interquartile range and standard deviation are measures of spread and not measures of centre.

6 0
3 years ago
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