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kvv77 [185]
3 years ago
8

Please Help Keep getting 6.4

Mathematics
2 answers:
elixir [45]3 years ago
8 0

Answer:

r = 3

Step-by-step explanation:

x^2 + 6x + y^2 - 8y = - 16

Take half the linear term and square it.

x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16

Add the squared amounts to the right.

x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16  

Combine on the right.

x^2 + 6x + 9 + y^2 - 8y + 16 = 9

Represent the 2 quadratics as perfect squares.

(x + 3)^2 + y - 4)^2 = 9

The radius is the square root of 9 which is 3

cestrela7 [59]3 years ago
8 0

Answer:

radius=3

Step-by-step explanation:

Given:

x^2 +6x +y^2 - 8y=-16

completing the squares

: x^2 +6x +9 = (x+3)^2

:y^2-8y+16 = (y-4)^2

(x+3)^2 + (y-4)^2 -9-16=-16

(x+3)^2 + (y-4)^2=-16+9+16

(x+3)^2 + (y-4)^2=9

Now comparing with standard equation of circle i.e. (x-h)^2 + (y-k)^2=r^2, we get

origin(h,k)= (-3,4)

r=3 !

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9- 4(2p+3) - 8p+7<br> how do i solve this ?
Sholpan [36]

Answer:

= -16p+4

Step-by-step explanation:

First we simplify:

9-4(2p+3)-8p+7

Then we distribute:

=9+(-4)(2p)+(-4)(3)+(-8p)+7\\=9+(-8p)+(-12)+(-8p)+7

Lastly, combine like terms:

=9+-8p+-12+-8p+7\\=(-8p+-8p)+(9+-12+7)\\=-16p+4

Hope this helps!

Have a good evening! :)

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     3
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4 years ago
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