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vladimir1956 [14]
4 years ago
11

Find the common ratio for the following sequence. 27, 9, 3, 1, ...

Mathematics
1 answer:
Elenna [48]4 years ago
7 0
The following ratio would be 1/3. Its a fraction so you would also be able to say 1.3. :)
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The area of a rectangle is 63m^2 and the length of the rectangle is 11m more than twice the width. Find the length and width.
AleksandrR [38]

Answer:

width = 3.5 m

length = 18 m

Step-by-step explanation:

area = length x width

x is the width then length = 2x + 11

x(2x + 11) = 63

2x^2 + 11x - 63 = 0

The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

with a = 2

       b = 11

       c = -63

substitute in the formula

x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)

x = [-11 +/- √(121 + 504)]/4

x = [-11 +/- √625]/4

x = (-11 +/- 25)/4

x1 = (-11 + 25)/4 = 14/4 = 3.5

x2 = (-11 - 25)/4 = -36/4 = -9

since width can't be a negative number, x is 3.5

length = 2x + 11 = 2(3.5) + 11 = 18

7 0
2 years ago
Triangle G Y K is shown. Angle G K Y is a right angle. Angle K G Y is 60 degrees and angle G Y K is 30 degrees. The length of G
Karo-lina-s [1.5K]

Answer:

Sqrt 3

Step-by-step explanation:

3 0
3 years ago
What is the volume of this sphere <br> Use π=3.14 and round your answer to the nearest hundredth
Alina [70]
The answer is 523.6 and all you have to do is round it to the nearest hundredth
7 0
3 years ago
Use the Distributive Property to rewrite each expression. <br><br> -7 (5 - n)
daser333 [38]
The answer is

-35 - 7n
8 0
3 years ago
A ladder is leaning against a building.The distance from the bottom of the ladder to the building is 6ft shorter than the length
Akimi4 [234]

Answer:

15 ft

Step-by-step explanation:

Hi, the illustration for the problem is a right triangle with:

hypotenuse (C)= the length of the ladder = L

horizontal side(A) = distance from bottom of the ladder to the building = L - 6

vertical side(B) = distance from the top of the ladder to the bottom of the building = L - 3

So, we can use Pythagoras formula:

A2 +B2= C2

(L – 6 )² + (L-3)² = L²

L²-12L+36+L²-6L+9 =L²

L2 -18L+45 =0

APPLYING QUADRATIC FORMULA WE OBTAIN:

L =15 OR L=3

If L=3

Vertical side = L-3 = 0 (Length can´t be 0)

So L=15

6 0
4 years ago
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