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3 years ago

Lines c and d are parallel lines cut by transversal p.

Mathematics

2 answers:

Alex17521 [72]3 years ago

5 0

Answer:

B.) ∠2 is congruent to ∠6.

bearhunter [10]3 years ago

4 0

First, let's start off, let us define what are corresponding angles. When a transversal, which is a line that passes through two parallel lines, then the angles in the same corners are congruent.

Using this definition, the angles ∠2 is congruent to ∠6.

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Katrina's margin error at 85% confidence interval: E=1.96*sqrt (p(1-p)/100) = 0.196 sqrt (1(1-p))

Mathew's margin error at 99% confidence interval: E= 2.58*sqrt (p(1-p)/400) = 0.129 sqrt (p(1-p))

Since both obtained same estimate of proportion (that is, value of p), it can be seen that Mathew's estimate will have a small error (That is, 0.129 is smaller than 0.196). This can be attributed to larger sample size although a wider confidence (99%) interval was considered.

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3 years ago

3x - 2x + 8 = 12; x = 4

vodomira [7]

Answer:

correct

Step-by-step explanation:

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2 years ago

Are all equilateral triangles acute?

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Step-by-step explanation:

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2 years ago

Kirby is four miles from the train station, from which a train is due to leave in 56 minutes. Kirby is walking along at 3 mph, a

Luda [366]

Let's assume that Kirby walks with a speed
$v_1 = 3 mph$
for a time $t_1$ , and that he runs with a speed
$v_2 = 12 mph$
for a time $t_2$ .

The total time available for Kirby to catch the train is:
$t=56 min = 0.93 h$
and this must be equal to the sum of the two times t1 and t2:
$0.93 = t_1 + t_2$

The distance Kirby should cover is
$S=4 m$
and this should be equal to the sum of the distances covered by walking and by running:
$4 = S_1 + S_2 = v_1 t_1 + v_2 t_2 = 3 t_1 + 12 t_2$

So we have a system of 2 equations:
$0.93 = t_1 + t_2$
$4 = 3 t_1 + 12 t_2$

If we solve the system, we find:
$t_1 = 0.80 h = 48 min$
$t_2 = 0.13 h = 8 min$

So, Kirby needs to run at least for 8 minutes in order to catch the train.

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3 years ago