Answer:
f(x) = x³ − 5x² − 16x + 80
Step-by-step explanation:
The degree is 3, so there are exactly 3 zeros.
The zeros are -4, 4, and 5.
f(x) = (x + 4) (x − 4) (x − 5)
f(x) = (x² − 16) (x − 5)
f(x) = x³ − 5x² − 16x + 80
<span>0.9% glucose solution means there are 0.9 g of glucose per 100 mL water.
</span><span> The concentration is required per litre for molar concentration:
0.9% glucose solution contains 9 g of glucose per 1000 mL or 1 L of water.
Molar mass of glucose is 180.16 g mol^-1 so 9 g = 9g/180.16 g mol^-1 = 0.05 moles
</span><span> 1 L of water contains 0.05 moles of glucose so molar concentration is 0.05 M or 0.05 mol/L </span>
Answer:
x < 1
Step-by-step explanation:
x+9<10
Subtract 9 from each side
x+9-9<10-9
x < 1
