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3 years ago

12x²-7x+10=0 by quadratic formula

Mathematics

1 answer:

gregori [183]3 years ago

4 0

Photo attached with the working out.

Hope it helped! :D
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A college professor never finishes his lecture before the end of the hour and always finishes his lectures within 2 min after th

Citrus2011 [14]

Answer:

Value of k is $\displaystyle\frac{3}{8}$

Step-by-step explanation:

We are given the following information in the question:

$f(x) = kx^2, 0\leq x \leq 2\\~~~~~~~= 0, \text{ otherwise}$

where x is the time elapses between the end of the hour and the end of the lecture.

We have to find the values of k.

Since, f(x) is the pdf, then,

$\displaystyle\int^\infty_{-\infty} f(x) = 1\\\\\displaystyle\int^2_{0} f(x) = 1\\\\\displaystyle\int^2_{0} kx^2 = 1\\\\k\bigg[\frac{x^3}{3}\bigg]^2_0 = 1\\\\k\times \frac{8}{3} = 1\\\\k = \frac{3}{8}$

Hence, value of k is $\displaystyle\frac{3}{8}$

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2 years ago

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lora16 [44]

Step-by-step explanation:

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Serggg [28]

Answer:

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Step-by-step explanation:

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2 years ago

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vivado [14]

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3 years ago

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Difference quotient

Nina [5.8K]

$f(x)=5x^2-5x-6
\\ \quad \\

\begin{cases}
f(\boxed{x+h})=5(\boxed{x+h})^2-5(\boxed{x+h})-6
\end{cases}\qquad thus
\\ \quad \\
\cfrac{f(x+h)-f(x)}{h}\qquad \textit{will be then}
\\ \quad \\
\cfrac{[5({x+h})^2-5({x+h})-6]\quad -\quad [5x^2-5x-6]}{h}
\\ \quad \\
\cfrac{[5(x^2+2xh+h^2)-5(x+h)-6]-[5x^2-5x-6]}{h}
$

$\cfrac{\underline{5x^2}+10xh+5h^2\underline{-5x}-5h\underline{-6}\underline{-5x^2}\underline{+5x}\underline{+6}}{h}\impliedby \textit{canceling those ones}
\\ \quad \\
\cfrac{10xh+5h^2-5h}{h}\impliedby \textit{common factor}
\\ \quad \\
\cfrac{5\underline{h}(2x+h-1)}{\underline{h}}$

and surely, you'd know what that is

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3 years ago