Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
3 3/4
Step-by-step explanation:
3/2/2/5 = 15/4
15/4 = 3 3/4
The original cost 35 more than this one. Therefore:
149+
