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Margaret [11]
3 years ago
5

8×25×23 strategies 4 grade

Mathematics
1 answer:
DerKrebs [107]3 years ago
4 0
8×25=200
and 
200×23=4600

so 8×25×23=4600
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If 3 = 1/2gt^2, make t the subject of the formula<br>​
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Answer:

t = √1.5/g

Step-by-step explanation:

1/2gt^2 = 3

Divide both sides by 1/2

gt^2 = 1.5

Divide both sides by g

t^2 = 1.5/g

Square root both sides

t = √1.5/g

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Graphing Method 2x+y=8
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Here is the answer on how to graph the equation

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During a cold winter, the temperature stayed below zero for 10 days (ranging from −20 to −5). The variance of the temperatures o
Serjik [45]

Answer:

The variance of the temperatures of the 10 day period must be at least zero.

Step-by-step explanation:

The variance is the expectation of the squared deviation of a random variable from its mean. It measures how far a set of numbers are spread out from their average value.

Its unit of measure corresponding to the square of the unit of measure of the variable. In this case, the variance of the temperatures is expressed in (°C)². The variance has a minimum value of 0.

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5 0
3 years ago
200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?
ziro4ka [17]

The sum of the equation is  = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

\sum_{j=1}^{200} 2 j^{2}+6 j

Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

is:

\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

Substitute the values into the formula and make sure to multiply by the front term.

(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

Evaluating same as above : 6 \sum_{j=1}^{200} j

we get: 120600

Add the results of the summations.

5373400 + 120600

= 5494000

The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

#SPJ4

6 0
2 years ago
When graphing a linear inequality, when can you NOT use (0, 0) as a test point to determine which side of a boundary line to sha
TEA [102]
When the point (0,0) is on the boundary line
8 0
4 years ago
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