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Flauer [41]
3 years ago
5

1 Point The circle below is centered at (-3, 2) and has a radius of 3. What is its equation?

Mathematics
1 answer:
arlik [135]3 years ago
8 0

Answer:

(x + 3)^2 + (y - 2)^2 = 9

Step-by-step explanation:

<u>Equation for a circle:  (x – h)^2 + (y – k)^2 = r^2</u>

<u />

<u>Step 1:  Determine what h, k, and r are</u>

<em>h is the x value of the point:  -3</em>

<em>k is the y value of the point:  2</em>

<em>r is the radius of the circle:  3</em>

<u>Step 2:  Plug in and solve</u>

(x – h)^2 + (y – k)^2 = r^2

(x – (-3))^2 + (y – (2))^2 = (3)^2

<em>(x + 3)^2 + (y - 2)^2 = 9</em>

<em />

Answer:  (x + 3)^2 + (y - 2)^2 = 9

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If (x+yi)(1-3i)=10 <br> Then x+y=
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