12 cos theta minus 16 sin theta is equal to zero find 2 sin theta + cos theta
2 answers:
Answer:
2sinθ + cosθ = 2
Step-by-step explanation:
12 cos θ - 16 sinθ = 0
=> 3 cos θ -4 sin θ = 0
=> tanθ = 3/4
let P = 3x
B = 4x
=> H= 5x
=> sinθ = P/H = 3/5
cosθ = B/H = 4/5
2sinθ + cosθ
= 2× 3/5 + 4/5
= 6/5+4/5
= 10/5
= 2
Answer:
2sinθ + cosθ = 2
Step-by-step explanation:
12 cos θ - 16 sinθ = 0
=> 3 cos θ -4 sin θ = 0
=> tanθ = 3/4
let P = 3x
B = 4x
=> H= 5x
=> sinθ = P/H = 3/5
cosθ = B/H = 4/5
2sinθ + cosθ
= 2× 3/5 + 4/5
= 6/5+4/5
= 10/5
= 2
=> 2sinθ + cosθ = 2
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