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Roman55 [17]
3 years ago
12

Given the following linear function, identify the slope and y-intercept of the function: x= 1/6x+7

Mathematics
2 answers:
Iteru [2.4K]3 years ago
5 0
The slope is 1/6 and the y intercept is 7
hope it helps
please mark as brainliest
DanielleElmas [232]3 years ago
4 0
The slope is 1/6 and the y intercept is 7
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f(x)=(x+3)(x-4) and g(x)=1/3(x+3)(x-4). the graphs of each are shown here. Which graph represents which polynomial function? exp
zvonat [6]

This is about interpretation of quadratic equation graphs.

<u><em>- The parabola that is continuous represents f(x) = (x+3)(x-4)</em></u>

<u><em>- The parabola that is a broken line represents g(x) = 1/3(x+3)(x-4)</em></u>

<u><em>- This is because calculating their y-intercept respectively corresponds with what is on the graph.</em></u>

  • We are given;

a) f(x) = (x+3)(x-4)

Let us confirm the x-intercept.

x-intercept here is when y = 0.

Thus, at y = 0; x + 3 = 0 and x - 4 = 0

Thus, at y = 0; x = -3 and y = 4

  • Let's now find the y-intercept;

y-intercept occurs when x = 0

Thus; y - intercept = (0 + 3)(0 - 4)

y - intercept = -12

  • Looking at the graph given, the only one that has it's y-intercept as -12 is the graph that has a continuous line.

  • This means the other graph that has dashed line would represent the other polynomial g(x)=1/3(x + 3)(x - 4)

Read more at; brainly.in/question/18896888

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2 years ago
1 kg = 2.2lb<br><br> 6.3lb = ___kg<br> show work
poizon [28]
\dfrac{1kg}{xkg}=\dfrac{2.2lb}{6.3lb}\ \ \ \ |cross\ multiply\\\\2.2x=1\cdot6.3\\\\2.2x=6.3\ \ \ |divide\ both\ sides\ by\ 2.2\\\\x=\dfrac{6.3}{2.2}\\\\x=\dfrac{63}{22}\\\\\boxed{6.3lb=2\frac{19}{22}kg\approx2.86kg}
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What is 3 times 4 brodie:)
Nata [24]

Answer:

the ans of this q should be 12 because 3 times 4 is 12 and the last word (brodie) the meaning of this word i dont know so yaa

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I am a prime number between 30 and 40. What number could I be?
Aneli [31]

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31 and 37 are the only prime numbers between 30 and 40

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These two polygons are similar. ​
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yea........ hi how you doinn

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