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spayn [35]
3 years ago
5

An art class is making a mural for their school which has a triangle drawn in the middle. The length of the bottom of the triang

le is x. Another side is 13 more than two times the length of the bottom of the triangle. The last side is 3 more than the bottom of the triangle. Write and simplify an expression for the perimeter of the triangle
Mathematics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

perimeter = 6x+15

Step-by-step explanation:

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Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle, or a parallelogram. The
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Answer:

2) ABCD is  a RECTANGLE.

Perimeter  =  30 units

Step-by-step explanation:

Here, the given points of the quadrilateral are:

A(6, –4), B(11, –4), C(11, 6), D(6, 6)

Now, if P(a,b) and Q(c,d) are any two given points, then the distance between them is given by DISTANCE FORMULA as:

PQ = \sqrt{(c-a)^2 + (d-b)^2

Use this to find the length of all 4 sides:

AB with coordinates A(6, –4), B(11, –4)  is given as:

AB = \sqrt{(11-6)^2 + (-4-(-4))^2} =  \sqrt{(5)^2 + 0} = 5

⇒ AB = 5 units

BC with coordinates B(11, –4), C(11, 6)  is given as:

BC = \sqrt{(11-11)^2 + (6-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

⇒ BC = 10 units

CD with coordinates C(11, 6), D(6, 6)  is given as:

CD = \sqrt{(11-6)^2 + (6-6)^2} =  \sqrt{(5)^2 + 0} = 5

⇒ CD = 5 units

AD with coordinates A(6, –4),D(6, 6)  is given as:

AD = \sqrt{(6-6)^2 + (-4-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

⇒ AD = 10 units

Now, here AB  = CD =  5 units, AD = BC  = 10 units

Also, in a RECTANGLE, OPPOSITE SIDES ARE EQUAL IN LENGTH.

Hence, ABCD is  a RECTANGLE.

Perimeter  = AB + BC+ CD  + AD = 5 + 10 + 5 + 10 = 30 units

8 0
3 years ago
Given the figure as marked, find the perimeter and area.
Kazeer [188]

Answer:

Step-by-step explanation:

Left triangle: it has two congruent legs because has an angle of 45 degrees

AB = \sqrt{ 2 * 6^2} = 6\sqrt{2} cm

the triangle on the the right is half on an equilateral one

BC = 12 cm

CH = 6√3 cm

AC= (6 + 6√3) cm

2p = 6 + 6√3 + 12 + 6√2 = 18 + 6√3 + 6√2 = 6(3 + √3 + √2) cm

Area = [6(1+√3)  * 6]/2 = 18(1+√3) cm^2

6 0
3 years ago
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