Answer:
x = 28 cm
Step-by-step explanation:
Given:
Area of link shaded regions = 84 cm²
Required:
The value of x (diameter of the semicircle/length of the rectangle)
Solution:
Diameter of the semicircle = 2r = x
Length of rectangle (L) = 2r = x
Radius of semicircle (r) = ½x
Width of rectangle (W) = radius of semicircle = ½x
Use 3.14 as π
Area of the link shaded regions = area of rectangle - area of semicircle
Thus:
Area of the link shaded regions = (L*W) - (½*πr²)
Plug in the values
84 = (x*½x) - (½*3.14*(½x)²)
84 = x²/2 - (1.57*x²/4)
84 = x²(½ - 1.57/4)
84 = x²(0.5 - 0.3925)
84 = x²(0.1075)
Divide both sides by 0.1075
84/0.1075 = x²
781.4 = x²
√781.4 = x
27.9535329 = x
x = 28 cm
Answer:
y =3x-1
Step-by-step explanation:
Parallel lines have the same slope, but different y intercepts :)
Answer: D) P(x) = -23
Step-by-step explanation:
Substitute 2 for x:
1 - 2(2)^2-3(2)^2+4(2)
Exponent
1-2(4)-3(8)+4(2)
Multiply
1-8-24+8
Combine like terms
-23
<em>Hope it helps <3</em>
<h2>option b. 52, 48 and 20</h2>
Step-by-step explanation:
<u>let's solve:-</u>
- To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .
soo
Pythagorean Theorem=
![\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }](https://tex.z-dn.net/?f=%5Cbold%20%5Cgreen%7B%28leg1%29%5E%7B2%7D%20%2B%28leg2%29%5E%7B2%7D%20%3D%28hypotenuse%29%5E%7B2%7D%20%7D)
<h2>_____________________________________</h2>
Here:-
![\bold \blue{leg \: 1 = 48} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bold \blue{ leg2 = 20} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bold\blue{hypotenuse = 52}](https://tex.z-dn.net/?f=%5Cbold%20%5Cblue%7Bleg%20%5C%3A%201%20%3D%2048%7D%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%5C%20%5Cbold%20%20%5Cblue%7B%20leg2%20%3D%2020%7D%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%5C%20%20%5Cbold%5Cblue%7Bhypotenuse%20%3D%2052%7D)
Putting values:-
![{48}^{2} + {20}^{2} = {52}^{2} \: \: \: \: \: \: \\ \\ 2304 + 400 = 2704 \\ \\ 2704 = 2704 \: \: \: \: \: \: \: \: \: \: \: \: \: \:](https://tex.z-dn.net/?f=%20%7B48%7D%5E%7B2%7D%20%20%2B%20%20%7B20%7D%5E%7B2%7D%20%20%3D%20%7B52%7D%5E%7B2%7D%20%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%5C%5C%20%20%5C%5C%202304%20%2B%20400%20%3D%202704%20%5C%5C%20%20%5C%5C%202704%20%3D%202704%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
<h2>_____________________________________</h2>
Answer: We can use tangent here to find the length of the flagpole
First, find the length of the building + the flag pole
tan 32 = x/300
x=300tan32=187.460805573
(length of building + flagpole)
find length of building
tan 30 = x/300
x=173.205080757
subtract
187.460805573-173.205080757=14.255724816
round, length of flagpole = 14 feet