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3 years ago

2 to the power of x plus 2 to the power of negative x equals 5/2

Mathematics

1 answer:

Sphinxa [80]3 years ago

7 0

Answer:

x=1

Step-by-step explanation:

2^x /1 + 1/2^x =5/2

2/1 +1/2 =5/2

4/2 + 1/2 =5/2

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Ber [7]

-5 1/3, -2 1/2, 3.75, 4.2 ( this is the order from least to greatest)

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3 years ago

Which is the slope of the like represented by the equation 2x+3y=-12

Burka [1]

slope = - $\frac{2}{3}$

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = - 12 into this form

subtract 2x from both sides

3y = - 2x - 12 ( divide all terms by 3 )

y = - $\frac{2}{3}$ x - 4 ← in slope- intercept form

with slope m = - $\frac{2}{3}$

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3 years ago

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What is Six less than y

bija089 [108]

Answer:

y-6

Step-by-step explanation:

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3 years ago

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If mZA = 4x – 12 and PZB = 24, solve for x.

Ronch [10]

Answer:

Step-by-step explanation:

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3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago