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Svetach [21]
3 years ago
13

Find a cubic function with the given zeros. Square root of seven., -Square root of seven., -4 f(x) = x3 + 4x2+ 7x - 28 f(x) = x3

+ 4x2 - 7x - 28 f(x) = x3 - 4x2 - 7x - 28 f(x) = x3 + 4x2 - 7x + 28
Mathematics
1 answer:
Talja [164]3 years ago
4 0

Answer:

f(x) = x^3 + 4x^2 - 7x - 28

Step-by-step explanation:

If the roots of this cubic function are Square root of seven,  -Square root of seven,  -4, then the factors must be (x^2 - 7)(x + 4).

Multiplying this out, we get f(x) = x^3 + 4x^2 - 7x - 28.

Note:  Please use " ^ " to indicate exponentiation.

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5 less than a number is more than 20
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What is the question here? All that is given is a statemnt with no question.

If you are trying to represent this statement mathamatically it woudl be:

x-5\ \textgreater \ 20
6 0
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Order the ratios from least to greatest<br> 16/24, 5 to 12, 6:13, 10:17, 13/28
saul85 [17]

Answer:

5/12, 6/13, 13/28, 10/17, 2/3

Step-by-step explanation:

First, simplify the ones that could be simplified.

2/3, 5 to 12, 6:13, 10:17, 13/28

<em>(okay apparently only the first could be simplified)</em>

<em />

You can look at all of them as fractions

2/3, 5/12, 6/13, 10/17, 13/28

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2 years ago
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lidiya [134]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
The length of a rectangle is 15 ft greater than its width. If each dimension is decreased by 2 ft, the area will be decreased by
padilas [110]

Answer:

length = 35ft, width = 20ft

Step-by-step explanation:

We are working with length (L), width (W), and area (A). We are asked to find the 2 dimensions. The question tells us that L = W + 15, so we can express L in terms of W. However, we still don't know what A is. Since we have 2 unknowns, we somehow need to develop 2 equations to get a solvable system.

We can set up the first equation using the relationship between L and W:

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We can set up the second equation using the information in the second sentence:

(W-2)(W+13)=A-106

Now we can plug the first equation, already isolated for A, into the second equation and solve for W:

(W-2)(W+13)=W(W+15)-106\\W^2+11W-26=W^2+15W-106\\4W=80\\W=20

A pretty nasty-looking equation actually becomes pretty easy to solve. We know the length is 15ft greater than the width, so if W=20, L=35.

6 0
3 years ago
PLEASE HELP I NEED TO PASS THIS TEST!!! (first actual answer gets brainliest)
Fed [463]

Answer:

W'(4, -2), X'(3, -4), Y'(1, -4), Z'(0, -2)

I hope this helps you. If you can give brainliest that would be greatly appreciated.

8 0
3 years ago
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