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krok68 [10]
3 years ago
6

A perpendicular bisector must be the same length as the segment it bisects True or false

Mathematics
1 answer:
USPshnik [31]3 years ago
6 0
False

A  perpendicular bisector does not have to be the same length as the segment it bisects, it only needs to bisect the segment through its center.

Hope this helps!
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100POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Alex Ar [27]
All of them involve y intercepts

f(x) means y
g(x) means  y

y intercept is where the graph crosses the y axis or when x=0 so set x=0

f(x)
x=0 when y=-7.5
y int=-7.5


g(x)
x=0
set x=0
y=3^0-7
y=1-7
y=-6


f(x) yint=-7.5
g(x) yint=-6


A. y int of f(x) is less than yint of g(x)
-7.5<-6
true

B. this is oposite of A so this is wrong

C. this says that g(x) has no yint, false

D. they yints are eqla
-7.5=-6
false




answer is A 
8 0
3 years ago
Read 2 more answers
3 3/7*-1/4
Shkiper50 [21]
Negative six sevenths -6/7
4 0
3 years ago
(08.05)
Readme [11.4K]
The mistake is in step 3:

I: −2m =−12 − 2n
II: 2m = 8 + 8n

the student set both right sides of the equations equal (−12 − 2n = 8 + 8n), but the left sides aren't equal: first equation has -2m, second has +2m so the signs of one of the equations must be inverted first
5 0
3 years ago
The length of a rectangle is 1 ft less than double the width, and the area of the rectangle is 21 ft^2. Find the dimensions of t
ICE Princess25 [194]

Let the width be w, then length = 2w - 1

Area = length times width = w(2w - 1) = 21.

Thus, 2w^2 - w = 21 or 2w^2 - w - 21 = 0

Solving the quadratic equation gives that w = 3.5.

Therefore, width is 3.5 ft and length is 2(3.5) - 1 = 6 ft.

4 0
3 years ago
Vivenne, John and nassim ran for 6th grade class president. Vivenne got four votes for every 3 votes that John got. Nassim got t
liq [111]

Answer:

John received 10% of the overall votes.

Step-by-step explanation:

Let us assume that the number of votes John got  = m

So, the number of votes Vivienne received =   3 times (John's share )

 = 3  times m   =  3 m

Also, The number of Votes Nassim received = 2 times ( Vivienne's share)

2 x (3 m)   = 6 m

Total Votes in the grade 6  

= Votes received by { John + Vivienne + Nassim}

= m + (3 m) + (6 m) = 10 m

Hence, the total number of students who voted in grade 6  = 10 m

\textrm{The percentage of John's Votes }  = \frac{\textrm{Number of votes John received}}{\textrm{Total number of votes }}  \times 100

= \frac{m}{10m}  \times 100 = 10

or, The percentage of John's Votes  = 10%

Hence, John received 10% of the overall votes.

3 0
3 years ago
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