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Musya8 [376]
4 years ago
5

What is the interquartile range of this data set? 2, 5, 9, 11, 18, 30, 42, 48, 55, 73, 81

Mathematics
1 answer:
4vir4ik [10]4 years ago
4 0

Answer:

I believe it is 63 although i may be doing the wrong formula. but as far as i can tell thats right.

Step-by-step explanation:

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Gymnast Clothing manufactures expensive soccer cleats for sale to college bookstores in runs of up to 500. Its cost (in dollars)
Natalija [7]

Revenue, R = 130x

Profit, P = Revenue – Cost

 P = R – C

P = 130x – 2950 + 6x + 0.1x^2

At P = 0

0 = -2950 + 136x +0.1x^2

X = 21.355, -1381.355

Therefore, manufacture greater than 21.355 items to make profit. 

3 0
3 years ago
Read 2 more answers
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
Write the equation of the line that has the indicated slope and contains the indicated point. Express the final equation in stan
OlgaM077 [116]

Answer:

y = 1/2x + 5

Step-by-step explanation:

Given :

Slope, m = 1/2

(x1, y1) = (6, 8)

y - y1 = m(x - x1)

y - 8 = 1/2(x - 6)

y - 8 = 1/2x - 3

y - 8 + 8 = 1/2x - 3 + 8

y = 1/2x + 5

Stamdard form of equation :

y = mx + c

Hence, equation is :

y = 1/2x + 5

7 0
3 years ago
Please review the image for the question
Flura [38]

Answer: y=1/3x^2-8/3x+10/3

Step-by-step explanation:

6 0
3 years ago
Look at the Hexagon below
Mama L [17]

Answer:

Angle 9: 60°

Angle 10: 30°

Side = radius = 40sqrt(x/3)

Area = [800sqrt(3)]x

Step-by-step explanation:

Total angle in a hexagon:

(6 - 2) × 180

720

Each interior angle:

720/6 = 120

angle 9 = 120/2 = 60

Angle 10 = 60/2 = 30

sin(60) = 20sqrt(x)/r

r = 20sqrt(x) ÷ sqrt(3)/2

r = 40sqrt(x/3)

Side:

sin(30) = ½s/(40sqrt(x/3))

½s = 20sqrt(x/3)

s = 40sqrt(x/3)

Area = (3sqrt(3))/2 × s²

Area = 3sqrt(3)/2 × 1600x/3

Area = [800sqrt(3)]x

4 0
3 years ago
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