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4 years ago

What is the interquartile range of this data set? 2, 5, 9, 11, 18, 30, 42, 48, 55, 73, 81

Mathematics

1 answer:

4vir4ik [10]4 years ago

4 0

Answer:

I believe it is 63 although i may be doing the wrong formula. but as far as i can tell thats right.

Step-by-step explanation:

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Gymnast Clothing manufactures expensive soccer cleats for sale to college bookstores in runs of up to 500. Its cost (in dollars)

Natalija [7]

Revenue, R = 130x

Profit, P = Revenue – Cost

P = R – C

P = 130x – 2950 + 6x + 0.1x^2

At P = 0

0 = -2950 + 136x +0.1x^2

X = 21.355, -1381.355

Therefore, manufacture greater than 21.355 items to make profit.

3 0

3 years ago

Read 2 more answers

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Write the equation of the line that has the indicated slope and contains the indicated point. Express the final equation in stan

OlgaM077 [116]

Answer:

y = 1/2x + 5

Step-by-step explanation:

Given :

Slope, m = 1/2

(x1, y1) = (6, 8)

y - y1 = m(x - x1)

y - 8 = 1/2(x - 6)

y - 8 = 1/2x - 3

y - 8 + 8 = 1/2x - 3 + 8

y = 1/2x + 5

Stamdard form of equation :

y = mx + c

Hence, equation is :

y = 1/2x + 5

7 0

3 years ago

Please review the image for the question

Flura [38]

Answer: y=1/3x^2-8/3x+10/3

Step-by-step explanation:

6 0

3 years ago

Look at the Hexagon below

Mama L [17]

Answer:

Angle 9: 60°

Angle 10: 30°

Side = radius = 40sqrt(x/3)

Area = [800sqrt(3)]x

Step-by-step explanation:

Total angle in a hexagon:

(6 - 2) × 180

720

Each interior angle:

720/6 = 120

angle 9 = 120/2 = 60

Angle 10 = 60/2 = 30

sin(60) = 20sqrt(x)/r

r = 20sqrt(x) ÷ sqrt(3)/2

r = 40sqrt(x/3)

Side:

sin(30) = ½s/(40sqrt(x/3))

½s = 20sqrt(x/3)

s = 40sqrt(x/3)

Area = (3sqrt(3))/2 × s²

Area = 3sqrt(3)/2 × 1600x/3

Area = [800sqrt(3)]x

4 0

3 years ago