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4 years ago

What is the interquartile range of this data set? 2, 5, 9, 11, 18, 30, 42, 48, 55, 73, 81

Mathematics

1 answer:

4vir4ik [10]4 years ago

4 0

Answer:

I believe it is 63 although i may be doing the wrong formula. but as far as i can tell thats right.

Step-by-step explanation:

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-1/2 + 4/9

stira [4]

Answer:

-1/18

Step-by-step explanation:

First, you have to change both fractions to have like denominators. The LCM of 2 and 9 is 18.

Second, you have to multiply -1/2 by 9/9 to get a denominator of 18. -1/2 x 9/9 is - 9/18.

Third, you have to multiply 4/9 by 2/2 to get a denominator of 18. 4/9 x 2/2 = 8/18.

Fourth, -9/18 + 8/18 = -1/18

Hope this helps!

4 0

3 years ago

Please help I asked this question earlier and nobody answered! :(

tatiyna

Answer:

Step-by-step explanation:

One way to tell is to put both equations into slope-intercept form. That form is usually written $y=mx+b$ where m is the slope and b is the y-intercept.

Solve the first equation for y.

$6x+2y=5 \\ 2y=-6x+5 \\ y=-3x+5/2$

The slope of this line is -3, and its y-intercept is 5/2.

Solve the second equation for y.

$y+3x=2\\y=-3x+2$

The slope of this line is -3 and its y-intercept is 2.

The lines are parallel because they have the same slope and different y-intercepts. There is no solution to the system.

8 0

3 years ago

What is the value of 4530 divided by 10³ A. 0.453 B. 4.530 C. 45.30 D. 453.0

goblinko [34]

The value of 4530 divided by 10^3 is B

4 0

3 years ago

Read 2 more answers

Plz solve. plz solve by this Friday thxx

Aneli [31]

Answer: About 22%
This is because all of her expenses add up to $800. $175 of those are for her phone and clothes. 175/800 equals about 22 percent. Exact answer is 21.875%

3 0

3 years ago

rom a group of 5 managers (Joon, Kendra, Lee, Marnie and Noomi), 2 people are randomly selected to attend a conference in Las Ve

andrezito [222]

Answer:

probability that Marnie and Noomi are both selected=0.1

Step-by-step explanation:

A group of 5 managers (Joon, Kendra, Lee, Marnie and Noomi), 2 people are randomly selected to attend a conference in Las Vegas.

the possibility of selecting 2 from 5 manages is 5C2 ways

$5C2= \frac{5!}{2!(5-2)!} =10$

There is only one choice of selecting Marine and Noomi from 5 managers

So probability of selecting Marine and Noomi is

$\frac{1}{10} =0.1$

5 0

3 years ago