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Reptile [31]
3 years ago
6

I am confused *-* Oh and have a great day!

Mathematics
2 answers:
Ratling [72]3 years ago
5 0

Answer:

Amelia rented a DVD and it was due to be returned on 26 November. She actually returned it to the shop on 12 December. The rental shop applies a fine of 9p for every day the DVD is overdue.

Work out the total fine paid by Amelia. Give your answer in £

pogonyaev3 years ago
5 0
I think it’s D but I’m not sure I hope it’s right
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Solve equation for x. X+16+3x=18+2x
mr_godi [17]
Let me know if u can see this picture

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4 years ago
Which congruency statements could be correct for the figures? Check all that apply. MNOP ≅ STUV MNPO ≅ TSVU NPOM ≅ VUTS OPNM ≅ T
jeka94

Answer:

NPOM ≅ VUTS

OPNM ≅ TUVS

Step-by-step explanation: Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent,  where, OM is congruent or equal to TS and in quadrilaterals NPOM and  VUTS-

since, the condition and, side UV=side  OM   follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

7 0
3 years ago
Read 2 more answers
If a 36-inch yardstick casts a 21-foot shadow, how tall is a building whose shadow is 168 feet?
MAVERICK [17]
The building would have to be 24 feet tall

36 inch is 3 ft
21/3=7
168/7=24
6 0
3 years ago
PLEASE HELP ASAP<br><br> Given the right information, can you construct a function?
iren [92.7K]
Yes, depending on which type of function depends on what information you need.
7 0
4 years ago
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Find a polynomial function of degree 3 with 2, i, -i as zeros.
sergiy2304 [10]

Answer:

p(x)= x^3-2x^2+x-2

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if \alpha , \ \beta \ \& \ \gamma are the zeros of the cubic polynomial , then ,

\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)

Here in place of the Greek letters , substitute 2,i and -i , we get ,

\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

\sf  \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}

Simplify using i = √-1 ,

\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )

Multiply by distribution ,

\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)

Simplify by opening the brackets ,

\sf\longrightarrow p(x)= x^3+x-2x^2-2

Rearrange ,

\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}

4 0
3 years ago
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