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goblinko [34]
3 years ago
14

Determine the value of xA 2 root6B6 root2C-6 root3D-12​

Mathematics
1 answer:
harina [27]3 years ago
4 0

Answer:

<u><em>B:  6 root 2</em></u>

Step-by-step explanation:

this is a right angled triangle having two sides perpendicular and base equal to 6cm

Using the Pythagorean theorem

(Hypotenuse)² = (perpendicular)² + (base)²

c²= (6)²+ (6)²= 36+36

c= √72= √36*2= 6√2= 6 root 2

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Answer:

Problem B: x = 12; m<EFG = 48

Problem C: m<G = 60; m<J = 120

Step-by-step explanation:

Problem B.

Angles EFG and IFH are vertical angles, so they are congruent.

m<EFG = m<IFH

4x = 48

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m<EFG = m<IFH = 48

Problem C.

One angle is marked a right angle, so its measure is 90 deg.

The next angle counterclockwise is marked 30 deg.

Add these two measures together, and you get 120 deg.

<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.

Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.

m<G = 180 - 120 = 60

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