Yes. Any number that can be written a fraction like that is rational.
The correct factorization is (3x - 2)(2x + 5).
In order to find this, we first have to set up parenthesis with the front being factors of 6x^2.
(3x ____)(2x _____)
Now we are going to try the factors of the last numbers in the end of these parenthesis. We can try these in different orders and then multiply to determine if we have the correct order. If for some reason we try them all and do not get the appropriate equation, we can try 6x and x as factors instead. However, we'll try -2 and 5 to see the correct result.
(3x - 2)(2x + 5)
6x^2 -4x + 15x - 10
6x^2 + 11x - 10 ---> this is the original. And therefore, it is the right factorization.
9-2+4 there it is im wrinting becuase i need more charecters
Step-by-step explanation:
(a^2+3b)/(c-2d)
substitute a=3,b=8,c=2,d=5
(3^2+3(8))/(2-2(5))
=(9+24)/(2-10)
=33/(-8)
=-4.125
Answer:
a
Step-by-step explanation:
(-1.00000005)^n
as n becomes very large, the function increases in both positive and negative direction.
If n=1, -1.00000005
if n=2, 1.0000001
if n= 3, -1.00000015
if n=20, 1.000001
if n=21, -1.00000105
