Answer:
4.5π ft³ or 14.14 ft³. Volume is a three dimensional unit of measure, meaning the units will be ft³.
Step-by-step explanation:
In order to solve this you need to know the volume formula for a sphere, which is (4/3)(π)(r³) where r is the radius. By plugging the the given value, 3/2, you get the volume to be 4.5π or 14.14 ft³.
Answer: 5 , 4.5
Step-by-step explanation:
Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.
Answer:
0.015 is the approximate probability that the mean salary of the 100 players was less than $3.0 million
Step-by-step explanation:
We are given the following information in the question:
Mean, μ =$3.26 million
Standard Deviation, σ = $1.2 million 100
We assume that the distribution of salaries is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Standard error due to sampling =
![\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1.2}{\sqrt{100}} = 0.12](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%20%5Cfrac%7B1.2%7D%7B%5Csqrt%7B100%7D%7D%20%3D%200.12)
P(mean salary of the 100 players was less than $3.0 million)
Calculating the value from the standard normal table we have,
![P(Z < -2.167) = 0.015 \\P( x < 3) = 1.5\%](https://tex.z-dn.net/?f=P%28Z%20%3C%20-2.167%29%20%3D%200.015%20%5C%5CP%28%20x%20%3C%203%29%20%3D%201.5%5C%25)
0.015 is the approximate probability that the mean salary of the 100 players was less than $3.0 million
That's true since it is absolute value.