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marin [14]
3 years ago
6

Find m < BCS if m< BCD = 174 and m< SCD = 150

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

∠SCD =150 and ∠BCD=174 (Given)

∠BCS + ∠SCD = ∠BCD (Segment Addition Postulate)

∠BCS + 150 = 174 (Substitution)

∠BCS = 24 (Subtraction Property of Equality)

Answer: 24

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At Dunkin Donuts the corn muffins they make represent 40% of the total muffins they bake everyday. On Monday they make 20 corn m
stellarik [79]

Answer:

50 muffins

Step-by-step explanation:

20 : 40%

y : 100%

\frac{20}{y} :\frac{40}{100}

y · 40 = 20 · 100

40y = 2000

40y ÷ 40 = 2000 ÷ 40

y = 50

8 0
3 years ago
Read 2 more answers
I need help desperately lol
yulyashka [42]

Answer:

Step-by-step explanation:

First find the shaded area. Ignore the fact that something is missing.

L = 16

w = 8

Area = L*w           Substitute the givens

Area = 16*8

Area = 128

Now consider the white area. It has a "length" of 4 and a width of 8

L = 4

w = 8

Area = 32

Now subtract 32 from 128

Area of shaded part = 128 - 32

Answer: 96 mm^2

6 0
2 years ago
Two step equation -5=d/4+3
Karolina [17]

Answer:

If you are looking for d the answer is -32.

Step-by-step explanation:

-5=d/4+3

-3         -3

(4)-8=d/4(4)

-32 =d

8 0
2 years ago
company x has 50 employees and company y has 60 employees. both companies have the same number of full-time employees, but compa
Sloan [31]

Using the simplification, company y has 17 number of part-time employees.

In the given question we have to find how many part-time employees does company y have.

From the question, company x has 50 employees and company y has 60 employees.

Both companies have the same number of full-time employees, but company y has 3 more than twice the number of part-time employees that company x has.

Let company x has A number of part-time employees.

According the given statement

Company y has number of part-time employees = 2A+3

Let company X and Y have B number of full-time employees.

So the total number of employees in company x;

A+B = 50....................(1)

The total number of employees in company x;

2A+3+B = 60

Subtract 3 on both side we get

2A+B=57....................(2)

Subtract Equation 2 and 1

2A+B-(A+B)=57-50

2A+B-A-B=57-50

A=7

Now putting the value of A in equation 1

7+B=50

Subtract 7 on both side we get

B=43

As, Company y has number of part-time employees = 2A+3

Company y has number of part-time employees = 2×7+3

Company y has number of part-time employees = 14+3

Company y has number of part-time employees = 17

Hence, company y has 17 number of part-time employees.

To learn more about simplification link is here

brainly.com/question/2804192

#SPJ4

8 0
1 year ago
Weights of American adults are normally distributed with a mean of 180 pounds and a standard deviation of 8 pounds. What is the
ahrayia [7]

Answer:

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 180, \sigma = 8

What is the probability that a randomly selected individual will be between 185 and 190 pounds?

This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So

X = 190

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 180}{8}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 185

Z = \frac{X - \mu}{\sigma}

Z = \frac{185 - 180}{8}

Z = 0.63

Z = 0.63 has a pvalue of 0.7357

0.8944 - 0.7357 = 0.1587

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

3 0
3 years ago
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