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Aneli [31]
4 years ago
9

4x+1-5x=5-(x+4) help me solve this

Mathematics
1 answer:
katen-ka-za [31]4 years ago
5 0

4x+1-5x=5-(x+4)

Do the  parenthesis first which’s

4x+1-5x=-5x-20

Now we have to combine the like terms

Which’s -x+1=-5x-20

Now we have to put the x together

-x+1=-5x-20

-x.      -x

1=4x-20

Also we need to put the x by itself so we will  add 20 to  both sides

1=4x-20

+20  +20

Which is 21=4x

Now we have to divide the both sides by 4 to get the x by itself

21/4=4x/4

So the answer will be 21/4=x

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12-2(n-1)=-18<br><br> aa help plzz
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Answer:

n=16

Step-by-step explanation:

Let's solve your equation step-by-step.

12−2(n−1)=−18

Step 1: Simplify both sides of the equation.

12−2(n−1)=−18

12+(−2)(n)+(−2)(−1)=−18(Distribute)

12+−2n+2=−18

(−2n)+(12+2)=−18(Combine Like Terms)

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Step 2: Subtract 14 from both sides.

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Step 3: Divide both sides by -2.

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Suppose the sample space for a probability experiment has 8 elements. If elements from the sample are selected without replaceme
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Answer: Number of ways =\dfrac{8!}{8!0!}\ or \ 1

Step-by-step explanation:

When there is no replacement , we use combination to find the number of ways to choose things.

Number of ways to choose r things out of  ( with out replacement) = ^nC_r=\dfrac{n!}{r!(n-r)!}

The number of ways to choose  8 things = ^8C_8=\dfrac{8!}{8!(8-8)!}=\dfrac{1}{0!}=1  [\because 0!=1]

Hence,  Number of ways =\dfrac{8!}{8!0!}\ or \ 1

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