The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for
is 9.
Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and
for 8<t<11.
A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.
B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.
C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.
D) In this we have to find the function at
when m belongs to
the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.
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The correct answer is 0.5 as a decimal as a fraction it is 5/10 = 1/2 so it is what ever one u need 1/2 or 5/10 or 0.5. Hope this helps! ;D
Any pictures so I can anwser?
Answer:
384√3 in²
Step-by-step explanation:
Given in the question a regular 6 sided polygon
To find it's area you have to use the following formula
<h3> 1/2 x perimeter x apothem</h3>
<em>Perimeter = the sum of the lengths of all the sides </em>
<em>Suppose length of one side = x</em>
<em>Apothem = a segment that joins the polygon's centre to the midpoint of any side that is perpendicular to that side = 8√3</em>
<em />
Since the polygon have 6 sides so
perimeter = 6x
<h3>x = 2(8√3)/√3</h3>
x = 2(8)
x = 16
perimeter = 6(16) = 96 in
plug values in the formula of area
<h3>1/2 x 96 x 8√3</h3>
384√3 in²