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Romashka-Z-Leto [24]
2 years ago
6

Nearly all social software systems include a(n) ________, which helps control your information flow.

Computers and Technology
2 answers:
laila [671]2 years ago
8 0
Dashboard

Nearly all social software systems include a(n) dashboard, which helps control your information flow.
Alekssandra [29.7K]2 years ago
4 0

Answer:

dashboard

Explanation:

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skelet666 [1.2K]
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6 0
3 years ago
Read 2 more answers
Which statement about muzzleloaders is true? All muzzleloaders are rifles. All muzzleloaders have only one barrel. Muzzleloaders
NeX [460]

Answer:

Muzzleloaders are early firearms that are loaded from the open end

Explanation:

A muzzleloader is any firearm into which the projectile and usually the propellant charge is loaded from the muzzle of the gun.

This is distinct from the more popular modern designs of breech-loading firearms.

Thus, muzzleloaders are early firearms that are loaded from the open end.

6 0
3 years ago
Identify the correctly constructed ALTER TABLE statement to add a UNIQUE constraint to the column customer_number with the const
SVEN [57.7K]

ALTER TABLE customer ADD CONSTRAINT customer_number_unique UNIQUE (customer_number);

5 0
2 years ago
Write the definition of a void function that takes as input two integer values, say n and m. The function returns the sum and av
hodyreva [135]

Answer:

void mn(int m, int n){

   int sum = 0;

int count = 0;

   if(m<n){

       for(int i = m;i<=n;i++){

           sum+=i;

       }

   }

   else{

       for(int i = n;i<=m;i++){

           sum+=i;

       }

   }

count = abs(m - n)+1;

   cout<<"Sum: "<<sum<<endl;

   cout<<"Average: "<<(float)sum/count;

}

Explanation:

This line defines the method

void mn(int m, int n){

This initializes sum and count to 0

   int sum = 0;

int count = 0;

This checks if m is less than n

   if(m<n){

This iterates from m to n and calculates the sum of numbers between this interval

<em>   for(int i = m;i<=n;i++){</em>

<em>            sum+=i;</em>

<em>        }</em>

<em>    }</em>

If otherwise,

   else{

This iterates from n to m and calculates the sum of numbers between this interval

<em>        for(int i = n;i<=m;i++){</em>

<em>            sum+=i;</em>

<em>        }</em>

<em>    }</em>

This calculates the range from m to n using absolute function

count = abs(m - n)+1;

This prints the calculated sum

   cout<<"Sum: "<<sum<<endl;

This calculates and prints the average

   cout<<"Average: "<<(float)sum/count;

}

<em>See attachment for complete program that includes the main (in c++)</em>

Download cpp
7 0
3 years ago
Write a program that reads in your question #2 Python source code file and counts the occurrence of each keyword in the file. Yo
scoray [572]

Answer:

Here is the Python program:

import keyword  #module that contains list of keywords of python

filename = input("Enter Python source code filename: ") # prompts user to enter the filename of a source code

code = open(filename, "r") # opens the file in read mode

keywords = keyword.kwlist #extract list of all keywords of Python and stored it into keywords

dictionary = dict() #creates a dictionary to store each keyword and its number of occurrence in source code

for statement in code: # iterates through each line of the source code in the file

   statement = statement.strip() # removes the spaces in the statement of source code  

   words = statement.split(" ") #break each statement of the source code into a list of words by empty space separator

   for word in words:# iterates through each word/item of the words list  

       if word in keywords:#checks if word in the code is present in the keywords list of Python  

           if word in dictionary: #checks if word is already present in the dictionary

               dictionary[word] = dictionary[word] + 1 #if word is present in dictionary add one to the count of the existing word

           else: #if word is not already present in the dictionary  

               dictionary[word] = 1 #add the word to the dictionary and set the count of word to 1

for key in list(dictionary.keys()): #iterates through each word in the list of all keys in dictionary  

   print(key, ":", dictionary[key])# prints keyword: occurrences in key:value format of dict

Explanation:

The program is well explained in the comments attached with each line of the program.  

The program prompts the user to enter the name of the file that contains the Python source code. Then the file is opened in read mode using open() method.

Then the keyword.kwlist statement contains the list of all keywords of Python. These are stored in keywords.

Then a dictionary is created which is used to store the words from the source code that are the keywords along with their number of occurrences in the file.

Then source code is split into the lines (statements) and the first for loop iterates through each line and removes the spaces in the statement of source code .

Then the lines are split into a list of words using split() method. The second for loop is used to iterate through each word in the list of words of the source code. Now each word is matched with the list of keywords of Python that is stored in keywords. If a word in the source code of the file is present in the keywords then that word is added to the dictionary and the count of that word is set to 1. If the word is already present in the dictionary. For example if there are 3 "import" keywords in the source code and if 1 of the import keywords is already in the dictionary. So when the second import keyword is found, then the count of that keyword is increased by 1 so that becomes 2.

Then the last loop is used to print each word of the Python that is a keyword along with its number of occurrences in the file.

The program and its output is attached in a screenshot. I have used this program as source code file.

7 0
3 years ago
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