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denis-greek [22]
3 years ago
13

Elapsed time is 6 hours & 44 minutes. End time is 10:42 a.m. what is the start time?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0
To do this problem, we would have to subtract the elapsed hour with the end time, and the same for the minutes.

End time minutes: 42

Elapsed time minutes: 44

42-44=-2

End time hour: 10

Elapsed hour: 6

10-6=4 hours.

So now we have 4 hours and -2 minutes as the start time, so we have to subtract an hour and subtract 2 from 60 minutes.

Start time is: 3:58 AM

~Hope I helped!~

lidiya [134]3 years ago
3 0
3:58 am, because 42-44 would give you 58 min, and 10-6 would be 4, but since you have to go 44 minutes in the past, you have to take out another hour.
(this is kind of hard to explain, just use the answer)
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If the point (a,3) lies on the graph of the equation 5x + y = 8, then a=<br>a.01<br>b.0-1<br>c.0-7​
fomenos

Answer:

A (a = 1)

Step-by-step explanation:

A coordinate point is always in the form (x,y) that means the first point is always x-coordinate and the second point is always y-coordinate.

The equation given is:

5x + y = 8

The point is (a,3), so that means x = a and y = 3

We substitute the values into the equation and find a. Shown below:

5x + y = 8

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6 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

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Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

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\mathrm{Switch\:sides}

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6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

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So,

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b=0,b=4

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3 years ago
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