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denis-greek [22]
3 years ago
13

Elapsed time is 6 hours & 44 minutes. End time is 10:42 a.m. what is the start time?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0
To do this problem, we would have to subtract the elapsed hour with the end time, and the same for the minutes.

End time minutes: 42

Elapsed time minutes: 44

42-44=-2

End time hour: 10

Elapsed hour: 6

10-6=4 hours.

So now we have 4 hours and -2 minutes as the start time, so we have to subtract an hour and subtract 2 from 60 minutes.

Start time is: 3:58 AM

~Hope I helped!~

lidiya [134]3 years ago
3 0
3:58 am, because 42-44 would give you 58 min, and 10-6 would be 4, but since you have to go 44 minutes in the past, you have to take out another hour.
(this is kind of hard to explain, just use the answer)
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7 0
3 years ago
HELP IM DESPRITE
scZoUnD [109]

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8

Step-by-step explanation:

45.5 + 15.5x < 175

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x < 8.35

Answer: 8

5 0
2 years ago
The seventh term of an arithmetic progression is equal to twice the fifth term. The sum
mario62 [17]

Answer:

a₁ = - 24

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₇ = 2a₅ , then

a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )

- a₁ - 2d = 0 → (1)

The sum to n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Given S_{7} = 84 , then

\frac{7}{2} (2a₁ + 6d) = 84

3.5(2a₁ + 6d) = 84 ( divide both sides by 3.5 )

2a₁ + 6d = 24 → (2)

Thus we have 2 equations

- a₁ - 2d = 0 → (1)

2a₁ + 6d = 24 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate d

- 3a₁ - 6d = 0 → (3)

Add (2) and (3) term by term to eliminate d

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6 0
3 years ago
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Arlecino [84]

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Answer:

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