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r-ruslan [8.4K]

3 years ago

14

A 36 m tall building is in the shape of rectangular prism.what is the volume of the building if the area of the ground floor is

639m2

1 answer:

Klio2033 [76]3 years ago

6 0

Answer:

ik bro sorry I didn't get back to you in a little bit and then I'll

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Please help!!!! This question is on my plato

Verizon [17]

Answer:

Its D

Step-by-step explanation:

29/1000= 0.029

8 0

3 years ago

Read 2 more answers

Find the length of AB and AC. please help...

Dmitry_Shevchenko [17]

Answer:

AB=30

AC=22.5

Step-by-step explanation:

8/15=12/x

x=22.5 (AC)

8/15=16/x

x=30 (AB)

4 0

3 years ago

Solve -9-8(1+4h)=-17

Mariulka [41]

-9-8(1+4h) = -17. We need to solve for h.
First, use the distributive property for 8(1+4h):
8(1+4h) = 8*1 + 8*4h = 8 + 32h

So -9-8(1+4h) = -17
-9 - (8+32h) = -17
-9 - 8 - 32h = -17
-17 - 32h = - 17
Add 17 on both sides to have the variables on a side and the numbers on the other:
-17 - 32h + 17 = -17 + 17
-32h = 0
divide both sides by -32 to get the variable h alone and its value on the other side:
(-32h)/-32 = 0/-32
h = 0.

So -9-8(1+4h) = -17 for h = 0.

You can recheck your answer (very important):
-9 - 8(1+4h) = -9 -8(1+4*0) = -9 - 8(1+0) = -9-8*1 = -9-8 = -17
The answer has been approved.

Hope this Helps! :)

5 0

3 years ago

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Juan reads a book with 368 pages. savannah reads a book with 172 fewer pages than juan's book. how many pages are in the book sa

Step2247 [10]

196 pages fewer than savannah

3 0

3 years ago

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Given f(x)=e^-x^3 find the vertical and horizontal asymptotes

Aleonysh [2.5K]

Given:

$f\mleft(x\mright)=e^{-x^3}$

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

$\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}$

Thus, y = 0 is the horizontal asymptote for the given function.

5 0

1 year ago