15-(3•4) = m
m=how many markers Tim has left.
The least common multiples of 2 and 3 would be 2 and 1 also 2 and is at its lowest multiple
6 √ 5
Simplify down and come to 6 √ 5
Answer:
Step-by-step explanation:sin
(
θ
)
=
40
41
Use the definition of sine to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.
sin
(
θ
)
=
opposite
hypotenuse
Find the adjacent side of the unit circle triangle. Since the hypotenuse and opposite sides are known, use the Pythagorean theorem to find the remaining side.
Adjacent
=
√
hypotenuse
2
−
opposite
2
Replace the known values in the equation.
Adjacent
=
√
(
41
)
2
−
(
40
)
2
Simplify
√
(
41
)
2
−
(
40
)
2
.
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Adjacent
=
9
Find the value of cosine.
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cos
(
θ
)
=
9
41
Find the value of tangent.
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tan
(
θ
)
=
40
9
Find the value of cotangent.
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cot
(
θ
)
=
9
40
Find the value of secant.
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sec
(
θ
)
=
41
9
Find the value of cosecant.
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csc
(
θ
)
=
41
40
This is the solution to each trig value.
sin
(
θ
)
=
40
41
cos
(
θ
)
=
9
41
tan
(
θ
)
=
40
9
cot
(
θ
)
=
9
40
sec
(
θ
)
=
41
9
csc
(
θ
)
=
41
40
We have cos( x - y ) = cosxcoy + sinxsiny <=> cos ( π - x ) = cosπcosx + sinπsinx <=> cos ( π - x ) = (-1)cosx + 0sinx = -cosx;
