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shtirl [24]
3 years ago
8

The length of a rectangle is twice the width. The area is 72 yd^2. Find the length and the width.

Mathematics
1 answer:
pochemuha3 years ago
4 0

Answer:

The length is 12yd and the width is 6yd.

Step-by-step explanation:

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I hate Geometry.... Help?
Usimov [2.4K]
Hello there,

Okay, Let's start with RS. So what I did was I subtracted (3x-4)-(4x+1) and the reason I did that was because (4x+1) equal's the whole length. And sense I dont know the length of RS yet. . . I will use the other length to find out. So when you calculate those both. Your correct answer is (x+5).

RS= x=5

Hope this helps.

~Jurgen
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the number of students in the art club is 3 more than twice the number of students in the drama clud.
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Jessica has a four-sided die, a six-sided die, and a 12-sided die. She rolls the three dice once. Let Z be the number of fours s
yawa3891 [41]

Answer:

The value of E [Z]  is 0.50.

Step-by-step explanation:

The expected value is computed using the formula:

E(X)=\sum x\cdot P(X= x)

Denote the three dices as follows:

X₁ = a four-sided die

X₂ = a six-sided die

X₃ = a 12-sided die

Define the indicator variables as follows:

I_{1}=\left \{ {{1;\ X_{1}=4} \atop {0;\ X_{1}\neq 4}} \right. \\\\I_{2}=\left \{ {{1;\ X_{2}=4} \atop {0;\ X_{2}\neq 4}} \right. \\\\I_{3}=\left \{ {{1;\ X_{3}=4} \atop {0;\ X_{3}\neq 4}} \right.

The probability of rolling a 4 in the three dices are as follows:

P(X_{1}=4)=\frac{1}{4}\\\\P(X_{2}=4)=\frac{1}{6}\\\\P(X_{3}=4)=\frac{1}{12}

Compute the value of E [Z] as follows:

E(Z)=E(I_{1})+E(I_{2})+E(I_{3})

         =(1\times\frac{1}{4})+(1\times\frac{1}{6})+(1\times\frac{1}{12})\\\\=\frac{3+2+1}{12}\\\\=\frac{6}{12}\\\\=\frac{1}{2}\\\\=0.50

Thus, the value of E [Z]  is 0.50.

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Nikitich [7]

Answer:

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2 years ago
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kondor19780726 [428]
These are all of the possible ratios:

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Please vote my answer brainliest. thanks!
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