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3 years ago

The length of a rectangle is twice the width. The area is 72 yd^2. Find the length and the width.

Mathematics

1 answer:

pochemuha3 years ago

4 0

Answer:

The length is 12yd and the width is 6yd.

Step-by-step explanation:

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Solve for m: m – 4.2 = 5.1

Fantom [35]

Answer:

M equals 9.3

Step-by-step explanation:

To get m alone add 4.2 to each side

4 0

2 years ago

Please help, I really need help Will mark as brainliest....

spayn [35]

Answer:

Step-by-step explanation:

A quarter circle is one fourth of a circle. To find the area of a quarter circle, find the area of the whole circle by using the formula A = pi * r^2 and then divide by 4. To find the perimeter of the quarter circle, find the circumference of the whole circle, divide by 4, and then add the radius twice.

4 0

3 years ago

Traci wants to buys rings that cost 50 dollars each. A jeweler is offering a offering a deal in which you buy 1 ring and get the

ddd [48]

1st ring=$50
2nd ring=$37.50
3rd ring=$25
$50+$37.50+$25 =$112.50 total cost before tax
$112.50 X 1.08=$121.5 total cost and tax
3 X $50 X 1.08=$162 total cost without discount deal
$162 - $121.50 =$40.50 savings

6 0

3 years ago

Find the solution of y = 5x - 4 for x = -6.

forsale [732]

Answer:

D (-6, -34)

Step-by-step explanation:

y = 5x - 4

Let x = -6

y = 5(-6) - 4

=-30 -4

= -34

x = -6, y= -34

6 0

3 years ago

Read 2 more answers

A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let X denote the number of green candies.

The probability of green candies is, p = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, n = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable X follows a binomial distribution with parameter n = 30 and p = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0

3 years ago