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3 years ago

A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches.

Mathematics

1 answer:

-Dominant- [34]3 years ago

8 0

Answer:

285.74

314 - 28.26 = 285.74

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A farmer ploughts his lands in 12 days if he use 5 tractors ow long will it if he uses 3 tractors?

saul85 [17]

Answer:

Step-by-step explanation:

By proportion it will be (5/3) * 12

= 60/3

= 20 days.

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2 years ago

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Help me please lol I will report if you troll

Ivenika [448]

Y = mx + b
m = slope, b = y intercept
Plug in the values

Solution: y = -2x + 3

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3 years ago

Solving a right triangle (round to the nearest tenth)

Inga [223]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for A

A = 180° - (90 + 46)° = 180° - 136° = 44°

----------------------------------------------------------------

tan46° = $\frac{opposite}{adjacent}$ = $\frac{b}{23}$

Multiply both sides by 23

23 × tan46° = b, thus

b ≈ 23.8 ( to the nearest tenth )

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cos46° = $\frac{adjacent}{hypotenuse}$ = $\frac{23}{c}$

Multiply both sides by c

c × cos46° = 23 ( divide both sides by cos46° )

c = $\frac{23}{cos46}$ ≈ 33.1 ( to the nearest tenth )

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3 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

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3 years ago

Your teacher asks you to find a recipe that includes two ingredients with a ratio of 1/2 cup/ 1/8 cup. a. give an example of two

Ksivusya [100]

A. Sugar And Brown Sugar (For Cookies)

B. No.

C 1/2 Cup (INGREDIENT) And 1/8 Cup (INGREDIENT)

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3 years ago