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3 years ago

Simplify the expression (9)^3/2

Mathematics

2 answers:

kari74 [83]3 years ago

7 0

$9^{ \frac{3}{2} } = \sqrt{9^3} = \sqrt{729} = 27$

Radda [10]3 years ago

7 0

Work is provided in the image attached.

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1/7=3/4x+1<br><br> Please help

zloy xaker [14]

Here, 1/7 = 3/4x + 1
3/4x = 1/7 - 1
3/4x = -6/7
x = -6/7 * 4/3
x = -2/7 * 4
x = -8/7

In short, Your Answer would be -8/7

Hope this helps!

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3 years ago

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3 years ago

Suppose that c(x)= (7x^3) - (84x^2) + (22,000x) is the cost of manufacturing x items. Find a production level that will minimise

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Free_Kalibri [48]

Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).

<h3>What are the mean and the standard error for each sample?</h3>

Considering the data given:

$\mu_S = 3.8, n = 175, s_S = \frac{1.7}{\sqrt{175}} = 0.1285$

$\mu_N = 4.8, n = 152, s_N = \frac{1.2}{\sqrt{152}} = 0.0973$

<h3>What is the mean and the standard error for the distribution of differences?</h3>

The mean is the subtraction of the means, hence:

$\overline{x} = \mu_S - \mu_N = 3.8 - 4.8 = -1$

The standard error is the square root of the sum of the variances of each sample, hence:

$s = \sqrt{s_S^2 + s_N^2} = \sqrt{0.1285^2 + 0.0973^2} = 0.1612$

<h3>What is the confidence interval?</h3>

It is given by:

$\overline{x} \pm zs$

We have a 95% confidence interval, hence the critical value is of z = 1.96.

Then, the bounds of the interval are given as follows:

$\overline{x} - zs = -1 - 1.96(0.1612) = -1.3$

$\overline{x} + zs = -1 + 1.96(0.1612) = -0.7$

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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1 year ago