The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
s = (1/2)√(a²+b²)
Answer:
SUM OF ALL ANGLES OF A TRIANGLE =180
THEREFORE,
X+8+2X-3+6X-5=180
9X=180
X=20.
THEREFORE,<J=X+8=20+8=28
<K=6X-5=6*20-5=120-5=115
<L=2X-3=2*20-3=40-3=37.
So firstly, multiply both sides by t: 
Next, add both sides by v0, and your answer will be: 
I got:
c) 18x-9=72
d) 3(6x-3)=72
e) x=4.5
If you need any explanations for the answers, please tell me!
