Calculate the hypotenuse( h ) using Pythagoras' identity
h =√(4² + 7²) = √(16 + 49) = √65
sinΘ = 4 / √65 ⇒ cscθ = √65 / 4
cosθ = 7/ √65 ⇒ secθ = √65 / 7
tanθ =
⇒ cotθ = 
Answer:
67.73625
Step-by-step explanation:
The dot (scalar) product is also the sum of products of corresponding vector components.
~a • ~b = 9·2.97 +6.75·6.075 +0·0 = 27.73 +41.00625 = 67.73625
The Answer is C: (24-15) x 4-3 x 2=30
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