Move all terms not containing x to the right side of the inequality.
x ≥ 13
Hope this helps! :)
and Happy Holloween!
~Zane
Answer:
vertex: (2,-18)
Step-by-step explanation:
y = ax² + bx + c
(-1,0) : a - b + c = 0 ...(1)
(5,0) : 25a +5b +c = 0 ...(2)
(0,-10): 0a + 0b + c = -10 c=-10
(1) x5: 5a - 5b + 5c = 0 ...(3)
(2)+(3): 30a + 6c = 0 30a = -6c = 60 a = 2
(1): 2 - b -10 = 0 b = -8
Equation: y = 2x² - 8x -10 = 2 (x² -4x +4) - 18 = 2(x-2)² -18
equation: y = a(x-h)²+k (h,k): vertex
vertex: (2,-18)
I am assuming you're doing a Punnet square, so you multiply each one. So on the top left box, it is -45x^2, the top right is 9x, bottom left is 35x, and bottom right is -7.
Answer:
5,888.67
Step-by-step explanation:
<h3>
Answer: 17</h3>
======================================================
Explanation:
This is a piecewise function. It's composed of 3 pieces of other functions. A piecewise function is a function that changes its identity based on what the input is.
We have three different situations here
- If t = 17, then h(t) = sqrt(17t) based on what the first row says
- If t = 19, then h(t) = -34/t which is the second row of the piecewise function.
- If t does not equal either 17 or 19 (ie t is anything but those values), then h(t) = 23-t
The notation h(17) means we want to evaluate h(t) when t = 17. So we'll use the first case mentioned above. Plug t = 17 into h(t) = sqrt(17t) to get...
h(t) = sqrt(17t)
h(17) = sqrt(17*17)
h(17) = sqrt(17^2)
h(17) = 17
In the last step, I used the rule that sqrt(x^2) = x when x is nonnegative.
