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anygoal [31]
3 years ago
8

Estimate the quotient using compatible numbers. 3,512 ÷ 9 30 400 300 40

Mathematics
1 answer:
madreJ [45]3 years ago
5 0

Answer:

400. just use simple devision and it'll tell you.

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Need help with this question
Tema [17]

The ratio is width over length.

Make a fraction with the width on top and the length on the bottom:

44/70

Both numbers are even and can be divided by 2,

so the simplified fraction becomes 22/35

6 0
4 years ago
10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
4 years ago
How do you 'undo' addition?
Triss [41]
By the way the question is worded, I would say you undo addition by subtraction. I hope this helped!
8 0
3 years ago
Read 2 more answers
How do I simplify this math problem?
mr Goodwill [35]
Basically, think of it as 3 / 1. 3√1 = 3/ 1 or 3/1 = 3 and 3√1 = 3
4 0
3 years ago
What is equivalent to 6(a − 2) + 8a ⋅2+3(a + 1)
hichkok12 [17]
81x81 divide use cals

3 0
3 years ago
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