Answer:
d. Competitive inhibition will decrease because the proportion of the active sites occupied by substrate will increase.
Explanation:
Enzymes are bio catalysts in living cells responsible for aiding biochemical reactions.
Their active sites are primary protein 3D structure for binding with substrates during reactions.
Enzymes reactions are usually affected by inhibitors(e.g methyl alcohol) which compete with the active site with the actual substrate(ethyl alcohol) ,
This is an example of competitive inhibition. The more ethyl alcohol available, the more active sites occupied, therefore denying the inhibitor methylalchol chances to the active site, thus preventing the formation of toxic formaldehyde, and more of non toxic substances from formation of more ADH-METHYL ALCOHOL COMPLEXES at the active sites
Answer:
E.coli is a bacterium which is preffered for transformation due to its rapid growth and high efficiency of introduction of DNA molecules into cells.
Tetracycline is an antibiotic used to treat several infections such as cholera, plague, brucellosis, and malaria etcetra.
Plasmid is a small, extrachromosomal DNA molecule present in cell which is seprated from chromosomal DNA and have ability to replicate independently.
When a plasmid resistant to tetracycline and kanamycine is inserted into E.coli, the process is called transformation. E.coli might not be able to survive due to absence of plasmid but the transformed strains having antibiotic tetracycline and kanamycine will probably be able to survive it.
Hence, the culture of bacteria carrying plasmid will be able to survive only.
Answer:
30 protein molecules per mRNA molecule
Explanation:
In this problem, it is necessary to have into account that the transcriptional process requires six (6) phosphate bonds to synthesize one (1) codon (i.e, each three nucleotides), and also discards 95% more energy to make mRNA, it means 19 times this amount of energy >> 6 x 19 = 114 bonds. In consequence, transcription requires 120 phosphate bonds (6 + 114 = 120), while translation requires four (4) phosphate bonds per codon. From this deduction, it is possible to find the number of protein molecules synthesized with regard to the energy cost of the translation process and the transcriptional process >>> 120 bonds (transcription) /4 bonds (translation) = 30 protein molecules.
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