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alisha [4.7K]
3 years ago
5

Life span development class

Biology
1 answer:
IceJOKER [234]3 years ago
3 0
True.
I know this because it happened to my family and friends families. Sorry if it’s wrong
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How do mutations lead to genetic diversity?
inn [45]

<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>mutation</u></em><em><u> </u></em><em><u>Mutations are changes to an organism's DNA and are an important driver of diversity in</u><u> </u><u>populations.</u><u> </u><u>This mutation has introduce a new allele into the population that increases genetic variation and may be passed on to the next generation.</u></em>

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2 years ago
¿Qué sucedería si por una epidemia desaparecieran las golondrinas marinas?
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Masteriza [31]

Answer:

An increase of 3,500 J

Explanation:

Given that,

Energy added by swimmer = 12000 J

Heat removed by the surrounding = 8500 J

We need to find the total change in energy. It can be calculated using the law of conservation of energy such as :

\Delta U=Q-W\\\\\Delta U=12000-8500\\\\\Delta U=3500\ J

As the change in energy is positive, it means that there is an increase of 3500 J.

5 0
3 years ago
How do particles move in solids, liquids, and gases.
zhenek [66]

Answer:

particles move fastest and with the highest kinetic energy in a gas, and slowest with the lowest kinetic energy in a solid. particles in a liquid are between the 2

8 0
3 years ago
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A new kind of tulip is produced that develops only purple or pink flowers. Assume that flower color is controlled by a single-ge
Sophie [7]

Answer:

a. purple allele (C) = 0.609, pink allele (c) = 0.391

b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476

Explanation:

Given -

Purple flowers - 847

Pink flowers - 153

The frequency of recessive genotype i.e

q^ 2 = \frac{153}{1000} \\q^ 2 = 0.153\\

Frequency of recessive allele i.e q is equal to

q = \sqrt{0.153} \\q = 0.391

As per hardy Weinberg's first equilibrium equation -

p + q = 1\\p = 1-q\\p = 1-0.391\\p = 0.609

Frequency of purple homozygous species

= p^2\\= 0.609^2\\= 0.371

Number of purple homozygous species = 0.371 * 1000= 371

Number of pink homozygous species = 0.153 * 1000= 153

Heterozygous species is equal to

(1-0.371-0.153)* 1000\\= 0.476 * 1000\\= 476

5 0
3 years ago
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