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shusha [124]
2 years ago
12

Find the 68th term of the arithmetic sequence -19, -33, -47, ...

Mathematics
1 answer:
garik1379 [7]2 years ago
3 0

Answer:

-957

Step-by-step explanation:

... -915, -929, -943, -957, -971, -985, -999 ...

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A box holding pennies, nickels and dimes contains thirteen coins with a total value of 83 cents. How many coins of each type are
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Answer:

The number of pennies,nickels and dimes are (p,n,d)=(3,4,6).

Further explanation:

Given:

A box holding pennies, nickels and dimes contains thirteen coins in a box.

Total value is 83 cents.

Calculation:

Consider p,n and d be the number of pennies, nickel and dimes.

Now, total is 13 coins so p+n+d=13

As we know that these following are US coin.

Penny=1 cent

Nickel=5 cents

Dime=10 cents

Step 1:

The value is already given as 83 cents that is 80+3 cents.

80 cents can be possible in many combinations as follows:

(N,D)=(0,8),(2,7),(4,6),(6,5),(8,4),(10,3),(12,2),(14,1),(16,0)

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Step 2:

The value of p is calculated as follows:

Substitute 4 for n, 6 for d in equation p+n+d=13 as follows:

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Thus, the number of pennies,nickels and dimes are (p,n,d)=(3,4,6).

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