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kogti [31]
2 years ago
14

PLS PLSSS HURRY I NEED HELP

Mathematics
1 answer:
Sloan [31]2 years ago
5 0

Answer:

look at the picture i have sent

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I just cant remember how to do these ones. been so long<br><br>Solve 2x – 5 = 7​
TEA [102]

Answer:

2x=7+5

2x=12

X=12/2=6

Kskwkjxu

8 0
2 years ago
What does AC=?<br> Round your answer to the nearest hundredth. <br><br> Please help
faltersainse [42]

Answer: About 3.06

Step-by-step explanation:

  We can use trigonometry functions to solve for AC. Let the ?, representing AC, be "x" in our mathematical work.

  Since we have the hypotenuse and x is adjacent to the angle given, I am going to use cosine.

      cos(θ) = \frac{adjacent}{hypotenuse }

      cos(40) = \frac{x}{4}

      0.766 ≈ \frac{x}{4}

      3.06 ≈ x

      x ≈ 3.06

4 0
2 years ago
HELP!! GEOMETRY
faust18 [17]

Answer:

you just rotate the

Step-by-step explanation:

3 0
2 years ago
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Double angle identity. Just 5 questions. Really need help as my teacher has been frustrated with me
BartSMP [9]

The double angle identities are

\sin(2x)=2\sin x\cos x

\cos(2x)=\cos^2x-\sin^2x

Then

2\sin\dfrac\pi6\cos\dfrac\pi6=\sin\left(\dfrac{2\pi}6\right)=\sin\dfrac\pi3

\cos^2\dfrac\pi{10}-\sin^2\dfrac\pi{10}=\cos\left(\dfrac{2\pi}{10}\right)=\cos\dfrac\pi5

The second identity together with the Pythagorean identity, \sin^2x+\cos^2x=1, gives us another equivalent expression:

\cos^2x-\sin^2x=\cos^2x-(1-\cos^2x)=2\cos^2x-1

so

2\cos^2(0.5)-1=\cos(2\cdot0.5)=\cos1

4 0
2 years ago
Read 2 more answers
Identify the terms and like terms in the expression.
Andreyy89

Answer:

1. The like terms are 11x and 2x and the terms are 11x and 2x

2. The like terms are 9x and -5x and the terms are 9x and -5x

3. the like terms are (21x and x) and (6 and -5) and the terms are 21x, 6, -x, and -5.

4. The like terms are (8x and -3x) and (14 and 1). And the terms are 8x, 14, -3x, and 1.

3 0
3 years ago
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