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Dafna11 [192]
4 years ago
5

Calculator

Mathematics
1 answer:
Sedaia [141]4 years ago
7 0

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

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At which value in the domain does f(x)=0 ?
lina2011 [118]

f(x)=0

Domain are the set of x values

f(x)=0 , we find all the x values where y =0

At x intercepts y is always 0

so we find all the x intercepts.

x intercepts are the points where the graph crosses x axis

In the graph we can see that the graph crosses x axis at

-2.5 , -0.75 and 1

-2.5 , -0.75 and 1 are the domain where f(x)=0

5 0
4 years ago
Read 2 more answers
For the linear equation 3x + 7y = 42: a. Determine the slope: b. Determine y- intercept if it exists: c. Express equation in slo
algol13

Answer:  The required answers are

(a) the slope of the given line is -\dfrac{3}{7}.

(b) y-intercept exists and is equal to 6.

(c) the slope-intercept form of the line is y=-\dfrac{3}{7}x+6.

Step-by-step explanation:  We are given the following linear equation in two variables :

3x+7y=42~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to :

(a) determine the slope,

(b) determine the y-intercept, if exists

and

(c) express equation in slope-intercept form.

We know that

The SLOPE_INTERCEPT form of the equation of a straight line is given by

y=mx+c, where m is the slope and c is the y-intercept of the line.

From equation (i), we have

3x+7y=42\\\\\Rightarrow 7y=-3x+42\\\\\Rightarrow y=\dfrac{-3x+42}{7}\\\\\\\Rightarrow y=-\dfrac{3}{7}x+6.

Comparing with the slope-intercept form, we get

\textup{slope, m}=-\dfrac{3}{7},\\\\\\\textup{y-intercept, c}=6.

Thus,

(a) the slope of the given line is -\dfrac{3}{7}.

(b) y-intercept exists and is equal to 6.

(c) the slope-intercept form of the line is y=-\dfrac{3}{7}x+6.

3 0
4 years ago
Please help and explain how to do this
Mnenie [13.5K]

Answer:

  4√3

Step-by-step explanation:

The distance formula applies. It tells you ...

  distance = √((x2 -x1)² +(y2 -y1)²)

Filling in the given values, you have ...

  distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)

  = √((-4√2+4√2)² +(2√3 +2√3)²)

  = √(0 + (4√3)²)

  distance = 4√3

___

We make use of the fact that ...

  a\sqrt{b}=\sqrt{a^2b}\\\\\sqrt{32}=\sqrt{16\cdot 2}=4\sqrt{2}\\\\2\sqrt{3}=\sqrt{2^2\cdot 3}=\sqrt{12}

3 0
3 years ago
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guapka [62]
All you have to do is 3.14×6×10 Which is 188.4
4 0
3 years ago
Could you help With these questions
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All I know is number 9. Is -2/5
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