Answer:
44
Step-by-step explanation:
Formula
Your scale is 2cm to 2units therefore the parameters are as follows
h=4
b1=9
b2=13
Find the common ratio for the following sequence. 27, 9, 3, 1, ... = 1/3
Find the common ratio for the following sequence. 1/2, -1/4, 1/8, -1/16, ... = -1/2
Find the common ratio for the following sequence. 1/2, -1/4, 1/8, -1/16, ...
= -1/2
Answer:
20×10=200mm
70:200
70/10=7
200/10=20
7:20 is your answer in it's simplest form
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
So 4 6/8= (32/4)+6/8=38/8
11 1/3=(33/3)+1/3=34/3
so 38/8+(34/3)
to add you must get the bottom number equall so
114/24+272/24=386/24=16 1/12
