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LenaWriter [7]
2 years ago
5

A car slows down at -5.00 m/s2 until it comes to a stop after traveling 15.0 m. How much time did it take to stop.

Mathematics
1 answer:
professor190 [17]2 years ago
4 0

Answer:

2.45 seconds to the nearest hundredth.

Step-by-step explanation:

Acceleration a = -5, distance s = 15, time  = ?.

Final  velocity = v =  0.

We need to use the equations of motion under constant acceleration.

v^2 = u^2 + 2as       where u is the initial velocity

0 = u^2 + 2*-5*15

u^2 = 150

so u = √150

Now we use v = u + at:

0 = √150 - 5t

t = √150/5

t = 2.45 seconds.

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At&t stadium home of the dallas cowboys of the NFL, seats approximately 11,200 more fans than Gillette Stadium, hime of the
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Answer:

At&t Stadium (Dallas cowboys) = 80,000 seats

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Step-by-step explanation:

The three stadiums all together have a total of 213,800 seats

We'll call X the Gillette Stadium seats.  We already had that the At&t stadium had X seats + 11,200 seats.  And also we knew that the CenturyLink Field had X seats - 3,800 seats.  The we can write the following equation,

X + (X + 11,200) + (X - 3,800) = 213,800 seats (the total of seats of the 3 stadiums together).  We need to find the value for X, that represents the Gillette stadium seats

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This is 3X + 11,200 - 3,800 = 213,800,

3X + 7,400 = 213,800,

3X = 213,800 - 7,400,

X = 206,400/3 seats

X = 68,800 seats

As At&t  is X + 11,200 seats, then it accommodates 80,000 people

And as CenturyLink Field is X - 3,800, it accommodates 65,000 people

7 0
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Step-by-step explanation:

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