Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
Answer:
3 inches
Step-by-step explanation:
(14+2x) × (15+2x) = 2(14×15)
210 +30x +28x + 4x² = 420
4x² + 58x - 210 = 0
2x² + 29x - 105 = 0
2x² + 35x - 6x - 105 = 0
x(2x + 35) - 3(2x + 35) = 0
(x - 3)(2x + 35) = 0
x = 3, -35/2(not possible)
Answer:
(7, 5)
Step-by-step explanation:
When reflecting over the x-axis, the only position that moves is the y-coordinate as it is going above the axis it was previously below. Since point F's original position was (7, -5) it is 5 spaces away from the x-axis. We move 5 places up to be even with the x-axis, then move up another 5 places to reflect the point to get F'.
Hope this Helps!
We know that
volume of a sphere=(4/3)*pi*r³----> (r/3)*(4*pi*r²)
and
surface area of sphere=4*pi*r²
so
the volume of a sphere=(r/3)*surface area of sphere
therefore
if r=3
volume of a sphere=(3/3)*surface area of sphere
volume of a sphere=surface area of sphere
if r> 3
the term (r/3) is > 0
so
volume of a sphere > surface area of sphere
if r<3
the term (r/3) is < 0
so
volume of a sphere < surface area of sphere
examples
1) for radius r=3 units
volume of a sphere=(4/3)*pi*3³----> 113.04 unit³
surface area=4*pi*3²----> 113.04 units²
volume is equal to surface area
2) for radius r=10 units
volume of a sphere=(4/3)*pi*10³----> 4186.67 unit³
surface area=4*pi*10²----> 1256 units²
volume is > surface area
3) for radius r=2 units
volume of a sphere=(4/3)*pi*2³----> 33.49 unit³
surface area=4*pi*2²----> 50.24 units²
volume is < surface area
