V=(1/3)πr²h
∴ dV/dt
=(π/3)[r²(dh/dt)+h2r(dr/dt)]
=(π/3)[(30)²(-2)+40(2)(30)(2)]
=(π/3)[-1800+4800]
=1600π in³/sec
Answer: 1600π in³/sec
3 fourths of an hour is : (3/4)
(3/4)*4=3 hours
hope this helps!
600,000 i believe . just do 6000x10= 60,000 then times that by 10
Answer:
Pythagorean theorem
Step-by-step explanation:
hope this helps
Answer:
To develop a molecular clock, you need to find which of the following?
a sequence of molecules
the rate at which changes occur in a type of molecule
how much total change has occurred in a type of molecule from two different species
how many molecules a species has
Step-by-step explanation:
To develop a molecular clock, you need to find which of the following?
a sequence of molecules
the rate at which changes occur in a type of molecule
how much total change has occurred in a type of molecule from two different species
how many molecules a species has
