Answer: Refer to the diagram below
- P ' is at (-7, 9)
- Q ' is at (1, 9)
- R ' is at (-6, 4)
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Explanation:
The diagram shows how point R moves to R'. We move up 2 units going from R(-6,0) to (-6,2). This lands us on the line of reflection. Then we move another 2 units up to land on (-6,4) which is the location of point R'.
The other points P and Q follow the same idea. Though the distances will be different from R. For P and Q, we'll move 7 units up to arrive at the line of reflection, then another 7 units to arrive at the proper locations of P' and Q', which are (-7,9) and (1,9) respectively.
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For this case we have the following vertices:
A (-1,1) --------> A '(3, -1)
B (-2.1)
C (-1,4)
We note that the translation rule is:
(x, y) -----------> (x + 4, y-2)
Applying the translacion rule we have:
B (-2, 1) -----------> (-2 + 4, 1-2) ------> B '(2, -1)
C (-1, 4) -----------> (-1 + 4, 4-2) ------> C '(3, 2)
Answer:
The image of vertex B or the image of Vertex C are:
B '(2, -1)
C '(3, 2)