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Trava [24]
3 years ago
11

Please help, On Saturday morning, Owen earned $21. By the end of the afternoon he had earned a total of $60. Enter an equation,

using x as your variable, to determine whether Owen earned $39 or $37 on Saturday afternoon.
Mathematics
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

$39 is the correct answer .

Step-by-step explanation:

Let the amount he earned on the afternoon  be x then

Amount earned in morning + Amount earned in afternoon=total amount

\$ 21 +\ x\ =\ \$ 60 \\\ x=\$60 -\$ 21\\x=\$  39

Therefore $39 is the amount he earned on afternoon .

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The reciprocal of 18 is. The reciprocal of is 2/3 is​
Leno4ka [110]

Answer:

1/18

3/2

Step-by-step explanation:

18 = 18/1 if the reciprocal means to flip the denominator and the numerator then just witched them so it would be 1/18

2/3 would be 3/2

4 0
3 years ago
Yesterday, between noon and midnight, the temperature dropped by 25.8°F. If the
SVEN [57.7K]

15.1 f

Step-by-step explanation:

-13.4+25.8= 15.1 F

8 0
2 years ago
Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3).
shusha [124]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x + 5y = 10 into this form

Subtract x from both sides

5y = - x + 10 ( divide all terms by 5 )

y = - \frac{1}{5} x +2 ← in slope- intercept form

with slope m = - \frac{1}{5}

• Parallel lines have equal slopes, hence

y = - \frac{1}{5} x + c ← is the partial equation of the parallel line

To find c substitute (1, 3) into the partial equation

3 = - \frac{1}{5} + c ⇒ c = \frac{16}{5}

y = - \frac{1}{5} x + \frac{16}{5} ← equation of parallel line

3 0
2 years ago
Read 2 more answers
Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

7 0
2 years ago
3 If the function f(x)=2x-3 and g(x)=x+1 then which of the following is a true statement? 2 (1) f(0)>g(0) (3) f (8)=g(8) (2)
lapo4ka [179]

Answer:2(1)

Step-by-step explanation:

3 0
2 years ago
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