3.14•6.5•7.5•18.4 <br> Round to the nearest hundreds

it rained nine days in the month of april .based on this ,what is the probaility that is does not rain on the first day of may?

attashe74 [19]

<h3>Answer: 7/10</h3>

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Explanation:

There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.

If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.

The empirical probability of it not raining on the first of May is therefore...

1 - (probability it rains)

1 - (3/10)

(10/10) - (3/10)

(10-3)/10

7/10

We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.

6 0

3 years ago

The year the Greek city of Helike disappeared is -1/5 times the year the US civil war ended. Let w represent the year the war en

Lostsunrise [7]

Answer:

ok so

-1/5x=w

w=1865

so -1/5x=1865

x=-9325

Hope This Helps!!!

5 0

3 years ago

Read 2 more answers

The distance between two locations, A and B, is calculated using a third location C at a distance of 15 miles from location B. I

Jobisdone [24]

We will first calculate ∠A:
∠∠A = 180° - ( 105° + 20 ° ) = 180° - 125° = 55°
Then we will use the Sine Law:
15 / sin 55° = AB / sin 20°
15 / 0.81915 = AB / 0.342
AB · 0.81915 = 15 · 0.342
AB · 0.81915 = 5.13
AB = 5.13 : 0.81915
AB = 6.26 ≈ 6.3 miles
Answer: The distance between the locations A and B is 6.3 miles.

4 0

4 years ago

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Renata and her family go through an average of more than 15 cans of sparkling water each day. They buy cases of 24 cans at $3.50

DENIUS [597]

Answer:

The inequality required to express the above condition is x ≥ 18.75

Step-by-step explanation:

Renata and her family go through an average of more than 15 cans of sparkling water each day.

The number of cases of 24 cans of sparkling water.

We can take the number of cases to be x.

Each case is said to cost $3.50.

An inequality for the number of cases that Renata's family go through in 24 days can be written as

x ≥ $\frac{15 \times 30}{24}$ ⇒ x ≥ $\frac{450}{24}$ ⇒ x ≥ 18.75

Therefore the inequality required to express the above condition is

x ≥ 18.75

3 0

3 years ago

Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = - $\sqrt{3}$

cos = $\frac{-\sqrt{3}}{3}$

Hope this helps!! :)

3 0

3 years ago

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3.14•6.5•7.5•18.4 Round to the nearest hundreds