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lisabon 2012 [21]

3 years ago

12

Tangent 2004-05-03-06-00_files/i0380000.jpg and secant 2004-05-03-06-00_files/i0380001.jpg intersect at point V. Find the length

of 2004-05-03-06-00_files/i0380002.jpg. Round the answer to the nearest tenth, if needed.

2 answers:

Finger [1]3 years ago

6 0

Where's the picture?

antiseptic1488 [7]3 years ago

4 0

Answer:

where is the pic

Step-by-step explanation:

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Answer:

x=45

Step-by-step explanation:

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tekilochka [14]

Step-by-step explanation:

$\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\$

$\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\$ and we have $sin^{2}+cos^{2} =1$

so $\frac{1+1+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2(1+cosA)}{sinA(1+cosA)} \\\\$

$\frac{2}{sinA}$ we have $\frac{1}{sin}=cosec\\$

<em>Finally </em> $2cosecA$ <em />

<em>I really hope this helps coz it took much time </em>

3 0

3 years ago

I need help pls help

Andreyy89

Answer:

[?] = 4

(the complete term is $4\frac{1}{2}\ \text{cups}$ )

Step-by-step explanation:

$8\ \text{cups} - 1\frac{1}{3}\ \text{cups} - 2\frac{1}{6}\ \text{cups} = (8-1-2)\ \text{cups} + \frac{-\frac{6}{3} - 1}{6}\ \text{cups} = 5\ \text{cups} + \frac{-3}{6}\ \text{cups} = 5\ \text{cups} + \frac{-1}{2}\ \text{cups} = 4\ \text{cups} + \frac{2 - 1}{2}\ \text{cups}$

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Step-by-step explanation:

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