All categories

2 years ago

it rained nine days in the month of april .based on this ,what is the probaility that is does not rain on the first day of may?

Mathematics

1 answer:

attashe74 [19]2 years ago

6 0

<h3>Answer: 7/10</h3>

==========================================================

Explanation:

There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.

If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.

The empirical probability of it not raining on the first of May is therefore...

1 - (probability it rains)

1 - (3/10)

(10/10) - (3/10)

(10-3)/10

7/10

We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.

You might be interested in

What number added to 66 is 167

denis-greek [22]

Answer:

101

Step-by-step explanation:

To figure this out, you would do 167 - 66 = 101

101 + 66 = 167

5 0

2 years ago

are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of

galben [10]

Answer:

The best estimate of the area of the larger figure is $693\ cm^{2}$

Step-by-step explanation:

step 1

<em>Find the scale factor</em>

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

$z=\frac{x}{y}$

we have

$x=12\ cm$

$y=9\ cm$

substitute

$z=\frac{12}{9}=\frac{4}{3}$ -----> the scale factor

step 2

<em>Find the area of the larger figure</em>

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

$z^{2}=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=390\ cm^{2}$

substitute and solve for x

$(\frac{4}{3})^{2}=\frac{x}{390}$

$(\frac{16}{9})=\frac{x}{390}$

$x=390*16/9=693.33\ cm^{2}$

4 0

2 years ago

7 times the difference of x and 8

Thepotemich [5.8K]

Answer:

7(x - 8)

Step-by-step explanation:

times means multiplication

difference means subtraction

7 times the difference of x and 8 -> 7 * (x - 8) -> 7(x - 8)

Simplify if needed.

7(x - 8)

~Distribute

2x - 56

Best of Luck!

8 0

2 years ago

Determine whether the improper integral converges or diverges, and find the value if it converges.

salantis [7]

Answer:

Integral will be diverging in nature

Step-by-step explanation:

We have given integral $\int_{5}^{\infty}\frac{3}{2}x^2dx$

Now after solving the integral

$[\frac{3}{2}\frac{x^3}{3}]$ limit from 5 to infinite

So $[\frac{3}{2}\frac{\infty^3}{3}]-[\frac{3}{2}\times \frac{5^3}{3}]=\infty$

As after solving integral we got infinite value so integral will be diverging in nature

7 0

2 years ago

In a fruit cocktail, for every 30 ml of orange juice you need 20 ml of apple juice and 50 ml of coconut milk. What proportion of

Orlov [11]

30+20+50 = 100 ml total. 20 ml is orange juice.

So, 30/100 reduce by dividing top and bottom by 30 gives

3/10 is the proportion of orange juice in the fruit cocktail.

Hope this helps! :)

7 0

1 year ago

Read 2 more answers

it rained nine days in the month of april .based on this ,what is the probaility that is does not rain on the first day of may?​

it rained nine days in the month of april .based on this ,what is the probaility that is does not rain on the first day of may?