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Strike441 [17]
3 years ago
14

What is the period, in seconds, of a simple pendulum of length 5 meters? Use the gravitonal constant g=9.8m/s^2 and round your a

nswer to two decimal places
Mathematics
2 answers:
Ivan3 years ago
7 0
Time = 2 PI * sq root (length / g)
Time = 2 PI * sq root (5 / 9.8)
<span> <span> <span> Time = 4.4879895051 </span> </span> </span>
<span>Time = 4.49

Source:
http://www.1728.org/pendulum.htm


</span>


SSSSS [86.1K]3 years ago
4 0
T = 2π√(l/g) 

<span>=> T = 2π√[5m/(9.8m/s²)] </span>

<span>=> T ≈ 4,49s </span>
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