What is the period, in seconds, of a simple pendulum of length 5 meters? Use the gravitonal constant g=9.8m/s^2 and round your a

Question

4 years ago

14

nswer to two decimal places

2 answers:

Ivan · Answer 1 · 2022-02-09T08:48:00+03:00

Ivan4 years ago

7 0

Time = 2 PI * sq root (length / g)
Time = 2 PI * sq root (5 / 9.8)
 Time = 4.4879895051 
Time = 4.49

Source:
http://www.1728.org/pendulum.htm

SSSSS [86.1K] · Answer 2 · 2022-02-09T07:17:42+03:00

4 0

T = 2π√(l/g)

=> T = 2π√[5m/(9.8m/s²)] 

=> T ≈ 4,49s