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3 years ago

9

Find the value of a and b a^2 + b^2 = 400

2 answers:

Oliga [24]3 years ago

7 0

Answer:

Step-by-step explanation:

a^2+b^2=400

a^2=400-b^2

a=sqrt(400-b^2) & -sqrt(400-b^2)

-----------------------------------------------

b^2=400-a^2

b=sqrt(400-a^2) & -sqrt(400-a^2)

ololo11 [35]3 years ago

3 0

Answer:

20

Step-by-step explanation:

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2 years ago

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Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

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$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

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$27 = 3(3a + b)$

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Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

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$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

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$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

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3 years ago

Select the statement that correctly describes the solution to this system of equations.

jasenka [17]

Selection C is appropriate.

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3 years ago

Prove identity tan 3x−tan 2x−tanx = tan 3xtan 2xtanx

NeX [460]

Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];

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2 years ago